应答检查-1 \f25 Java -1\f6

Question

我正在尝试向我当前的Java添加-1答案检查，但我不知道如何启动它。因此，当用户输入-1时，它将立即从循环中断。

所以输出结果应该如下所示：

$100000的Tax是$100000“，Income，Tax再次输入income，(-1停止程序)：

下面是我目前的代码，希望有人能帮助我:)

import java.util.Scanner;

public class Question3 
{
    public static void main (String[] args)
    {
        Scanner keyboard = new Scanner(System.in);

        double Income, Tax = 0;
        char Answer;
        int counter = 0;

        System.out.print("Enter Income: $");
        Income = keyboard.nextDouble();

        if (Income <= 20000)
        {
            Tax = 0;
        }
        if (Income > 20000 && Income < 30000)
        {
            Tax = (Income - 20000) * 0.02;
        }
        else if (Income > 30000 && Income < 40000)
        {
            Tax = ((Income - 30000) * 0.035) + 200;
        }
        else if (Income > 40000 && Income < 80000)
        {
            Tax = ((Income - 40000) * 0.07) + 550;
        }
        else if (Income > 80000 && Income < 120000)
        {
            Tax = ((Income - 80000) * 0.115) + 3350;
        }
        else if (Income > 120000 && Income < 160000)
        {
            Tax = ((Income - 120000) * 0.15) + 7950;
        }
        else if (Income > 160000 && Income < 200000)
        {
            Tax = ((Income - 160000) * 0.18) + 13950;
        }
        else if (Income > 200000 && Income < 240000)
        {
            Tax = ((Income - 200000) * 0.19) + 21150;
        }
        else if (Income > 240000 && Income < 280000)
        {
            Tax = ((Income - 240000) * 0.195) + 28750;
        }
        else if (Income > 280000 && Income < 320000)
        {
            Tax = ((Income - 280000) * 0.20) + 36550;
        }
        else if (Income > 320000)
        {
            Tax = ((Income - 320000) * 0.22) + 44550;
        }
        else
        {
            System.out.println ("Invalid Input");
        }


        System.out.printf("Tax for $%.2f is $%.2f\n", Income, Tax);
        System.out.print("Enter income again, (-1 to stop the program): ");
        Answer = keyboard.next().charAt(0);
    }
}

Answer 1

首先，没有循环，尽管您应该使用循环。你应该这样做：

// if-else-if chain
if(Income == -1){
return;
}

如果这是您想要的，那么当用户输入-1作为收入时，它应该返回void，这会中断程序。