我在这里遵循了演示:https://github.com/SheetJS/js-xlsx/tree/master/demos/electron
我可以将一个excel文件拖到我的电子应用程序中。
documentation 说,您可以使用以下命令访问每个单元:
for(var R = range.s.r; R <= range.e.r; ++R) {
for(var C = range.s.c; C <= range.e.c; ++C) {
var cell_address = {c:C, r:R};
/* if an A1-style address is needed, encode the address */
var cell_ref = XLSX.utils.encode_cell(cell_address);
}
}如何在下面的代码中使用它?我获得了存储在test变量中的文件内容,但我无法访问它。文档中缺少那里的信息。
var do_file = (function() {
return function do_file(files) {
var f = files[0];
var reader = new FileReader();
reader.onload = function(e) {
var data = e.target.result;
data = new Uint8Array(data);
test = XLSX.read(data, {type: 'array'});
console.log(test);
};
reader.readAsArrayBuffer(f);
};
})();我不知道如何开始,提前谢谢
发布于 2018-02-16 21:15:11
它是这样的:
var do_file = (function() {
return function do_file(files) {
var f = files[0];
var reader = new FileReader();
reader.onload = function(e) {
var data = e.target.result;
data = new Uint8Array(data);
//process_wb(XLSX.read(data, {type: 'array'}));
/* read the file */
var workbook = XLSX.read(data, {type: 'array'}); // parse the file
var sheet = workbook.Sheets[workbook.SheetNames[0]]; // get the first worksheet
/* loop through every cell manually */
var range = XLSX.utils.decode_range(sheet['!ref']); // get the range
for(var R = range.s.r; R <= range.e.r; ++R) {
for(var C = range.s.c; C <= range.e.c; ++C) {
/* find the cell object */
console.log('Row : ' + R);
console.log('Column : ' + C);
var cellref = XLSX.utils.encode_cell({c:C, r:R}); // construct A1 reference for cell
if(!sheet[cellref]) continue; // if cell doesn't exist, move on
var cell = sheet[cellref];
console.log(cell.v);
};
reader.readAsArrayBuffer(f);
};
})();发布于 2020-04-09 19:46:22
通常,您可以访问具有标准excel坐标的单元格,如
console.log(sheet['My Sheet Name']['B3'].v);在这里查看完整的数据类型:https://github.com/SheetJS/sheetjs/blob/master/README.md#cell-object
https://stackoverflow.com/questions/48816940
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