如果swift中存在特定字符，则从数组中删除字符串

Question

我正在编写一些Swift代码来遍历字符串数组( teams )，如果存在来自另一个数组(charsToRemove)的特殊字符，则从teams数组中删除该项。或者，我也可以将不包含特殊字符的项添加到数组中。以下是一些示例数据：

teams = ["lime", "teal/gold", "red-2", "orange", "orange(6)", "blue-7" ... ]
charsToRemove = [ "(", ")", "-", " ", "/" ... ]

最终结果应该如下所示：

teams = ["lime", "orange"]

我已经尝试了几次循环，但正在寻找可能是最好的路线。团队数组和特殊字符有点长，但不想在这里粘贴太多。

Answer 1

您可以使用字符串方法rangeOfCharacter(from: CharacterSet)来检查它是否找到某个字符集的范围，并使用它来过滤您的数组：

let teams = ["lime", "teal/gold", "red-2", "orange", "orange(6)", "blue-7"]
let charsToRemove = [ "(", ")", "-", " ", "/" ]
let cs = CharacterSet(charactersIn: charsToRemove.joined())
let filtered = teams.filter({ $0.rangeOfCharacter(from: cs) == nil })
print(filtered)   // ["lime", "orange"]

Answer 2

您可以在阵列上使用单个filter操作。在过滤器内部，您只需要调用charsToRemove.contains(where:)来检查teamName是否包含charsToRemove的任何元素，如果不包含，则将团队名称保留在过滤后的数组中。

let teams = ["lime", "teal/gold", "red-2", "orange", "orange(6)", "blue-7" ]
let charsToRemove = [ "(", ")", "-", " ", "/"]
let filteredTeams = teams.filter({ teamName -> Bool in
    charsToRemove.contains(where: { teamName.contains($0) }) == false
})

Answer 3

Leo's answer的一种更可重用(也更干净)的方法是扩展Array

extension Array where Element == String {
    /// Returns a new array after applying the filter
    var cleaned: [Element] {
        let charSet = CharacterSet(charactersIn: " ()-/") // note the space
        return filter { $0.rangeOfCharacter(from: charSet) == nil }
    }
}

let teams = ["lime", "teal/gold", "red-2", "orange", "orange(6)", "blue-7"]
print(teams.cleaned) // prints: ["lime", "orange"]

或者扩展Sequence，如果你想扩大它的应用范围：

extension Sequence where Element == String {
    /// Returns a new array after applying the filter
    var cleaned: [Element] {
        let charSet = CharacterSet(charactersIn: " ()-/") // note the space
        return filter { $0.rangeOfCharacter(from: charSet) == nil }
    }
}

let teams = ["lime", "teal/gold", "red-2", "orange", "orange(6)", "blue-7"]
print(teams.cleaned) // prints: ["lime", "orange"]

let set = Set(teams)
print(set.cleaned) // prints: ["orange", "lime"]

(注：Set__'s未排序)