根据每个员工的优点从高到低对他们进行排名

Question

创建两个表emp_merits (meritid，empid，date，meritpoints)，emp1(empid，empname)每个员工每个月都会根据他们的表现获得绩效积分。因此，同一员工在表中可以有多个具有不同积分的条目。列出特定员工在特定日期之间收到的所有绩效(此处输入empid)根据员工的绩效分数从高到低对每个员工进行排名

到目前为止，我已经尝试了这个查询

select   empid , sum (meritpoints) as totalmerits , (DENSE_RANK()OVER (PARTITION BY empid ORDER BY meritpoints desc)) AS rank from emp_merit 
  group by empid,meritpoints 
  order by empid ,totalmerits desc

Answer 1

你可以试试这个：

SELECT @rownum := @rownum + 1 AS rank, a.*  
FROM (
SELECT empid, sum(meritpoints) AS totalmerits
FROM emp_merits 
GROUP BY empid
ORDER BY totalmerits) a, (SELECT @rownum := 0) r ;

您可能需要在WHERE子句中指定日期。

Answer 2

您可以使用变量实现dense_rank()：

select empid, totalmerits,
       (@rn := if(@m = totalmerits, @rn,
                  if(@m := totalmerits, @rn + 1, @rn + 1)
                 )
       ) as rank
from (select empid, sum(meritpoints) as totalmerits
      from emp_merit 
      group by empid
      order by totalmerits desc
     ) e cross join
     (select @m := -1, @rn := 0) params;