我有一个包含大量就业信息的表,我使用listagg列出了每个用户的所有就业,每个用户在一行上,而不是最大解码路由。使用listagg可以工作,但我想将其限制在前5个示例中。一些员工列出了30多个工作岗位。
select distinct emp.id_Staff,
count (*) as cnt,
LISTAGG (emp.employer_name || '('|| emp.job_title || ')', ', ')
WITHIN GROUP (ORDER BY emp.employer_name) AS Employ_info
from (
SELECT distinct em.id_Staff, em.employer_name,
em.job_title, em_job_status
FROM employment em
where em.job_status = 'Active'
) emp
group by emp.id_Staff发布于 2017-12-14 03:17:46
您可以使用row_number()枚举值。然后在listagg()中使用case只获取前五条记录:
select e.id_Staff,
count(*) as cnt,
listagg(case when seqnum <= 5 then e.employer_name || '('|| e.job_title || ')' end, ', ')
within group (order by e.employer_name) AS Employ_info
from (select e.*,
row_number() over (partition by e.id_staff order by e.id_staff) as seqnum
from (select distinct em.id_Staff, em.employer_name, em.job_title, em_job_status
from employment em
where em.job_status = 'Active'
) e
) e
group by e.id_Staffhttps://stackoverflow.com/questions/47799631
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