从wordpress调用php页面
从wordpress调用php页面
提问于 2017-10-27 15:22:21
我已经在wordpress中修改了function.php，并使用快捷代码从wordpress菜单中调用了php页面。我可以连接和显示php页面。在php页面中，无需从下拉列表中选择值即可初始显示所有记录。但是，当我更改下拉列表中的值，而不是根据下拉列表显示过滤的记录时，页面将转到wordpress索引页面。我怀疑onaction命令作为提交，它不会停留在被调用的php页面，而是转到wordpress的索引页面。
<?php
$selected = '';
function get_options($select) {
$categories = ['Select Category' => 0, 'Information Technology' => 1, 'Management' => 2];
$options = '';
while (list($k, $v) = each($categories)) {
if ($select == $v) {
$options .= '<option value="' . $v . '" selected>' . $k . '</option>';
} else {
$options .= '<option value="' . $v . '" >' . $k . '</option>';
}
}
//var_dump($options);
//echo var_dump($options)."<br>";
return $options;
}
require_once('dbconnect.php');
if (isset($_POST['categories'])) {
$selected = $_POST['categories'];
echo $selected;
}
if ($selected == 1) {
$selectedcat = 'Information Technology';
$selectsql = "SELECT * FROM courses where ccategory='$selectedcat'";
} else if ($selected == 2) {
$selectedcat = 'Management';
$selectsql = "SELECT * FROM courses where ccategory='$selectedcat'";
} else {
$selectsql = "SELECT * FROM courses";
}
//require_once('dbconnect.php');
//include('header-basic-light.php');
//$selectsql="SELECT * FROM courses";
$res = (mysqli_query($con, $selectsql));
if (!mysqli_query($con, $selectsql)) {
die(mysqli_error($con));
}
mysqli_close($con);
//header('Location:index.php');
?>
<HTML>
<head>
//<title>"View Information"</title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
</head>
<body>
<div class="container">
<div class="row">
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
<label for="categories">Select the Category : </label>
<select name="categories" style="width:250px;" onchange="this.form.submit();">
<?php echo get_options($selected); ?>
</select>
</form>
<h2>View Information</h2>
<table class="table">
<tr>
<th>#</th>
<th>cname</th>
<th>start_date</th>
<th>duration</th>
<th>Remarks</th>
<th>Options</th>
</tr>
<?php
while ($r = mysqli_fetch_assoc($res)) {
?>
<tr>
<td><?php echo $r['cno']; ?></td>
<td><?php echo $r['cname']; ?></td>
<td><?php echo $r['start_date']; ?></td>
<td><?php echo $r['duration']; ?></td>
<td><?php echo $r['remarks']; ?></td>
<?php if ($r['ccategory'] == 'Information Technology') {
$catnum = 1;
}
if ($r['ccategory'] == 'Management') {
$catnum = 2;
} ?>
<td><a href="loadpage.php?id=<?php echo $catnum; ?>">Details  </a>
</tr>
<?php } ?>
</table>
</body>
</html>回答 1
Stack Overflow用户
发布于 2017-10-27 16:53:29
短代码的使用是必需的吗？为什么不创建一个page-slug.php，通过一个子主题覆盖它，并通过标准的固定链接函数获得重定向和urls？
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原文链接：
https://stackoverflow.com/questions/46969609
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