awk或sed命令，用于根据分隔符从文本文件中提取行

Question

我的文件说'file.txt‘有下面的内容，

---
controller-name: RAID-1
host-power: on
has-error: No
info-valid: Yes
controller-health: Good
---
controller-name: RAID-2
host-power: on
has-error: No
info-valid: Yes
controller-health: Bad
...

我想使用---作为每个控制器的分隔符来提取行。类似控制器的东西会给我第一个控制器和第二个控制器的controller1的详细信息。

我试着搜索，但没有找到任何相关的答案。

Answer 1

使用awk

基于一些假设，下面两个示例可以用来逐一搜索控制器配置，如果这不是您要编辑的配置，请您的问题并清楚地向我们介绍。

任一

# which will print and exit
# search for controller-name, increment variable
# print contents and exit

awk -v controller=1 '
         f && /^---/{exit}
         /^controller-name/{c++}
         f=c==controller
       ' infile

或

# which will save inside array
# used --- as row separator
# whenever controller-name awk finds, that line is saved in array
# in end block access it by a[0], a[1]....

awk -v RS='---' '
           /controller-name:/{
               gsub(/^\n|\n$/,"");
               a[c++]=$0
           }
           END{
              print a[0]
           }
          ' infile

测试结果：

输入：

$ cat infile 
---
controller-name: RAID-1
host-power: on
has-error: No
info-valid: Yes
controller-health: Good
---
controller-name: RAID-2
host-power: on
has-error: No
info-valid: Yes
controller-health: Bad
...

输出-1：

$ awk -v controller=1  'f && /^---/{exit}/^controller-name/{c++}f=c==controller' infile 
controller-name: RAID-1
host-power: on
has-error: No
info-valid: Yes
controller-health: Good

$ awk -v controller=2 'f && /^---/{exit}/^controller-name/{c++}f=c==controller' infile 
controller-name: RAID-2
host-power: on
has-error: No
info-valid: Yes
controller-health: Bad
...

输出-2：

$ awk -v RS='---' '/controller-name:/{gsub(/^\n|\n$/,"");a[c++]=$0}END{print a[0]}' infile 
controller-name: RAID-1
host-power: on
has-error: No
info-valid: Yes
controller-health: Good

$ awk -v RS='---' '/controller-name:/{gsub(/^\n|\n$/,"");a[c++]=$0}END{print a[1]}' infile 
controller-name: RAID-2
host-power: on
has-error: No
info-valid: Yes
controller-health: Bad
...