在model2的树状视图中显示model1中的字段

Question

我想要显示payroll.adjustment.lines中的字段employee_id，并从payroll.adjustment模型的树视图中显示它。有可能吗？他们有关系。

从payroll.adjustment模型

adjustment_lines = 
fields.One2many('payroll.adjustment.lines','adj_id',string="Adjustment 
lines")

从payroll.adjustment.lines模型

adj_id = fields.Many2one('payroll.adjustment',string="Payroll 
Adjustment",ondelete='cascade')

在我的xml中

<record id="payroll_adjustment_tree_view" model="ir.ui.view">
        <field name="name">payroll_adjustment.tree</field>
        <field name="model">payroll.adjustment</field>
        <field name="arch" type="xml">
            <tree string="Payroll Adjustment" colors="red:state == 
            'void';green:state == 'draft';blue:state=='confirm'">
                <field name="doc_num"/>
                <field name="company_id"/>
                <field name="adjustment_lines"/>
                <field name="date_from"/>
                <field name="date_to"/>
                <field name="state"/>
            </tree>
        </field>
    </record>

这个

<field name="adjustment_lines"/>

仅显示(2条记录)，不显示员工姓名。请帮帮我。谢谢

我尝试了下面的答案，这就是结果。显示为false的员工姓名

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这是我的树视图，在这里我从行中调用了字段，并将其从payroll.adjustment模型显示为树视图。

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这是我的树视图的输出，它只显示(记录)

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Answer 1

当您覆盖模型payroll.adjustment.line的name_get()方法时，它可以工作。下面的代码示例希望是不言自明的，并且是适用于您的情况的通用示例：

from odoo import models, fields, api


class MyModel(models.Model):
    _name = "my.model"

    another_model_ids = fields.One2Many(
        comodel_name="another.model", inverse="my_model_id",
        string="Another Model Entries")


class AnotherModel(models.Model):
    _name = "another.model"

    my_model_id = fields.Many2One(
        comodel_name="my.model", string="My Model")
    number = fields.Integer(string="A Number")
    yet_another_model_id = fields.Many2One(
        comodel_name="yet.another.model", string="Yet Another Model")

    @api.multi
    def name_get(self):
        # with context flags you can implement multiple
        # possibilities of name generation
        # best example: res.partner
        res = []
        for another_model in self:
            res.append((another_model.id, "{} {}".format(
                another_model.number,
                another_model.yet_another_model_id.name)))
        return res


class YetAnotherModel(models.Model):
    _name = "yet.another.model"

    name = fields.Char(string="Name")

my.model将是你的payroll.adjustment，而yet.another.model将是employee_id背后的模型。