Flask的DispatcherMiddleware与普洛特利的破折号玩得不好

Question

我有一个现有的Flask web应用程序，我想将现有的Dash应用程序(a Plotly Flask app)合并到它中。作为Flask's documentation recommends，我使用DispatcherMiddleware来实现这一点：

flask_app = Flask(__name__) # App with both apps attached to it 
app = Flask(__name__) # Existing Flask App 
dash_app = Dash(__name__) # Dash app 

dash_app.config.supress_callback_exceptions = True

# Use DispatcherMiddleware to route separate apps into one
flask_app.wsgi_app = DispatcherMiddleware(app, {'/dash': dash_app.server})

我们最终运行flask_app

if __name__ == "__main__":
    flask_app.run(debug=True)

但是，当我访问127.0.0.1:<port>/dash/时，网页上出现以下错误：

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我在控制台日志中看到以下内容：

127.0.0.1 - - [30/Aug/2017 11:11:02] "GET /dash HTTP/1.1" 301 -
127.0.0.1 - - [30/Aug/2017 11:11:02] "GET /dash/ HTTP/1.1" 200 -
127.0.0.1 - - [30/Aug/2017 11:11:03] "GET /_dash-layout HTTP/1.1" 404 -
127.0.0.1 - - [30/Aug/2017 11:11:03] "GET /_dash-dependencies HTTP/1.1" 404 

如何才能为我的Dash应用正确加载布局？

Answer 1

这就是我克服这个问题的方法。不是很漂亮，但很有效。

您需要run.py：

from werkzeug.wsgi import DispatcherMiddleware
from werkzeug.serving import run_simple
from server import server
from dash_app  import app as app1
from flask_app import app as app2

app = DispatcherMiddleware(server, 
                           {'/myflaskapp': app2})
if __name__ == '__main__':
    run_simple('localhost', 5000, app, use_reloader=True)

您的server.py将如下所示：

from flask import Flask, render_template

server = Flask(__name__)

@server.route('/')
def server_root():
    return render_template('index.html')

您的dash_app.py：

import dash
from server import server
app = dash.Dash(name='mydash', sharing=True, server=server, url_base_pathname='/mydash')

最后是你的flask_app.py：

from flask import Flask
app = Flask(__name__)
@app.route("/news")
def news():
    return render_template('news.html')

你的新闻在/myflaskapp/ flask_app

你的dash_app地址是/mydash