如何制作具有多个RSS源的RSS提要？

Question

取自a closed Stack post，如何将其修改为使用多个RSS源，并打印大量(5-10) RSS地址中的最新帖子列表？添加更多逗号分隔不起作用。

(注意:此代码仍然适用于WordPress博客，2017年8月)

<?php
$rss = new DOMDocument();

$rss->load('http://the .rsss or .xmls');
$feed = array();

foreach ($rss->getElementsByTagName('item') as $node) {
    $item = array ( 
        'title' => $node->getElementsByTagName('title')->item(0)->nodeValue,
        'desc' => $node->getElementsByTagName('description')->item(0)->nodeValue,
        'link' => $node->getElementsByTagName('link')->item(0)->nodeValue,
        'date' => $node->getElementsByTagName('pubDate')->item(0)->nodeValue,
        'image' => $node->getElementsByTagName('thumbnail')->item(0)->getAttribute('url')
        );

    array_push($feed, $item);
}
?>

Answer 1

您可以将您的rss urls放在一个数组中，并按如下方式遍历每个urls：

  $rss_urls = array(
    'http://firsturl.rss',
    'http://secondurl.rss',
    'http://thirdurl.rss',
  );


  $feed = array();

  foreach($rss_urls as $rss_url){

    $rss = new DOMDocument();
    $rss->load($rss_url);

    foreach ($rss->getElementsByTagName('item') as $node) {
      $item = array ( 
        'title' => $node->getElementsByTagName('title')->item(0)->nodeValue,
        'desc' => $node->getElementsByTagName('description')->item(0)->nodeValue,
        'link' => $node->getElementsByTagName('link')->item(0)->nodeValue,
        'date' => $node->getElementsByTagName('pubDate')->item(0)->nodeValue,
        'image' => $node->getElementsByTagName('thumbnail')->item(0)->getAttribute('url')
      );

      array_push($feed, $item);
    }
  }
?>