我正在尝试更新表中client_id = '5‘和invoice_number = '11’的行和列中的多个数据
我的表tbl_particulars
我的代码:
<table class="table table-bordered">
<tr>
<th>Date</th>
<th>Car No.</th>
<th>Particulars</th>
<th>Rate</th>
<th>Amount</th>
</tr>
<?php
$sql = "SELECT * FROM tbl_particulars WHERE client_id = '5' AND invoice_number = '11'";
$query = mysql_query($sql);
while($row = mysql_fetch_assoc($query)) {
?>
<tr>
<td width="200px" nowrap="nowrap"><table>
<tr>
<td>From<br>
<input type="hidden" name="numbers" value="3">
<input type="hidden" name="ids[]" value="<?php echo $row['id'] ?>">
<input type="text" name="date_from[]" value="<?php echo $row['date_from'] ?>" class="form-control" placeholder="DD/MM/YYYY"></td>
<td> </td>
<td>To<br>
<input type="text" name="date_to[]" value="<?php echo $row['date_to'] ?>" class="form-control" placeholder="DD/MM/YYYY"></td>
</tr>
</table></td>
<td width="100px"><input type="text" name="car_no[]" value="<?php echo $row['car_no'] ?>" class="form-control"></td>
<td width="250px"><table>
<tr>
<td><select name="particulars[]" class="form-control">
<option value="">--Please Select ur Duty--</option>
<option value="Local 80 Kms. & 8.00 Hrs. Duty" <?php if($row['particulars']=="Local 80 Kms. & 8.00 Hrs. Duty") echo 'selected="selected"'; ?> >Local 80 Kms. & 8.00 Hrs. Duty</option>
<option value="Upto" <?php if($row['particulars']=="Upto") echo 'selected="selected"'; ?>>Upto</option>
<option value="Extra Kms." <?php if($row['particulars']=="Extra Kms.") echo 'selected="selected"'; ?>>Extra Kms.</option>
<option value="Extra Hrs." <?php if($row['particulars']=="Extra Hrs.") echo 'selected="selected"'; ?> >Extra Hrs.</option>
<option value="Local Nights" <?php if($row['particulars']=="Local Nights") echo 'selected="selected"'; ?> >Local Nights</option>
<option value="Parking Toll Tax" <?php if($row['particulars']=="Parking Toll Tax") echo 'selected="selected"'; ?> >Parking Toll Tax</option>
<option value="Out Station" <?php if($row['particulars']=="Out Station") echo 'selected="selected"'; ?> >Out Station</option>
</select></td>
<td style="vertical-align:text-top !important">  @   </td>
<td width="100px"><input type="text" value="<?php echo $row['quantity'] ?>" name="quantity[]" class="form-control"></td>
</tr>
</table></td>
<td width="80px"><input type="text" name="rate[]" class="form-control" value="<?php echo $row['rate'] ?>" onChange="CalcGST()"></td>
<td width="80px"><input type="text" name="amount[]" class="form-control" value="<?php echo $row['amount'] ?>" onChange="CalcGST()"></td>
</tr>
<?php } ?>
<tr>
<td colspan="5"><button type="submit" name="update_invoicee" class="btn btn-info">Save & Continue</button></td>
</tr>
</table>
</div>
</form>
我的Php脚本:
<?php if(isset($_POST['update_invoicee'])){
$s = "UPDATE `tbl_particulars` SET";
for($i=0;$i<$_REQUEST['numbers'];$i++)
{
$s .="(
date_from='".$_REQUEST['date_from'][$i]."',
date_to='".$_REQUEST['date_to'][$i]."',
car_no='".$_REQUEST['car_no'][$i]."',
particulars='".$_REQUEST['particulars'][$i]."',
quantity='".$_REQUEST['quantity'][$i]."',
rate='".$_REQUEST['rate'][$i]."',
amount='".$_REQUEST['amount'][$i]."' WHERE id='".$_REQUEST['ids'][$i]."'),";
}
$s = rtrim($s,",");
if(!mysql_query($s))
echo mysql_error();
else
echo "<script>alert('Records Updated')</script>";
} ?>
现在脚本不工作,给出以下错误:
错误语法pr�s de '( date_from='newvalue',date_to='newvalue',car_no='newvalue‘�la ligne 1
发布于 2017-08-20 20:17:10
您收到的语法错误是由于SET关键字后的"(“符号造成的。它不允许在一个查询(MySQL Reference)中设置具有多个set或WHERE的多个语句。
可以将条件表达式放到每个字段中,并为所有接收到的is连接查询字符串(some example)。但这真的太多了-每个字段和复杂的代码都需要一个额外的循环来格式化这个查询(考虑一下将来编写、调试、审查和支持它)。
https://stackoverflow.com/questions/45780672
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