GraphiQL返回零变异

Question

我正在使用带有Sequelize的GraphQL，并且我有一个返回null的突变。

我尝试过用几种不同的方法来改变变异的解析器，但当我用GraphiQL测试它时，它总是返回null。

下面是用几种不同的方式编写的解析器：

1-最初我的想法是在promise中添加包装功能。

    resolve(root, args) {
        return new Promise((resolve, reject) => {
            db.record.findOne({ where: { UID: args.UID } })
                .then(record => {
                    let newArr = undefined
                    if (record.watched == null) {
                        newArr = [args.value]
                    } else {
                        let old = record.watched
                        newArr = old.concat([args.value])
                    }
                    db.record.update({ watched: newArr }, { where: { UID: args.UID } })
                        .then(record => {
                            resolve(record)
                        })
                })
        })
    }

2-在这里，我返回一个承诺。

    resolve(root, args) {
        db.record.findOne({ where: { UID: args.UID } })
            .then(record => {
                let newArr = undefined
                if (record.watched == null) {
                    newArr = [args.value]
                } else {
                    let old = record.watched
                    newArr = old.concat([args.value])
                }
                return db.record.update({ watched: newArr }, { where: { UID: args.UID } })
            })
    }

3-下面我直接返回了记录。

    resolve(root, args) {
        db.record.findOne({ where: { UID: args.UID } })
            .then(record => {
                let newArr = undefined
                if (record.watched == null) {
                    newArr = [args.value]
                } else {
                    let old = record.watched
                    newArr = old.concat([args.value])
                }
                db.record.update({ watched: newArr }, { where: { UID: args.UID } })
                    .then(record => {
                        return record
                    })
            })
    }

Answer 1

问题是您没有从您的解析器返回任何内容，并且您没有正确使用promises。尝试：

resolve(root, args) {
    return db.record.findOne({ where: { UID: args.UID } })
        .then(record => {
            let newArr = undefined
            if (record.watched == null) {
                newArr = [args.value]
            } else {
                let old = record.watched
                newArr = old.concat([args.value])
            }
            return db.record.update({ watched: newArr }, { where: { UID: args.UID } });
        });
}