当我们膨胀一个布局时,它会被缓存吗?如果我没记错的话,我读到过膨胀缓存XML是为了提高性能。对吗?缓存的内容到底是什么?
发布于 2020-07-21 17:59:52
从android.content.res下的ResourcesImpl类中,我得到了一些线索,当从XML.In inflater.inflate()膨胀视图时,有一个内部缓存机制,有一个负责解析XML的XmlResourceParser对象。这个对象是从ResourcesImpl类中名为loadXmlResourceParser的方法中获得的。方法是-
/**
* Loads an XML parser for the specified file.
*
* @param file the path for the XML file to parse
* @param id the resource identifier for the file
* @param assetCookie the asset cookie for the file
* @param type the type of resource (used for logging)
* @return a parser for the specified XML file
* @throws NotFoundException if the file could not be loaded
*/
@NonNull
XmlResourceParser loadXmlResourceParser(@NonNull String file, @AnyRes int id, int assetCookie,
@NonNull String type)
throws NotFoundException {
if (id != 0) {
try {
synchronized (mCachedXmlBlocks) {
final int[] cachedXmlBlockCookies = mCachedXmlBlockCookies;
final String[] cachedXmlBlockFiles = mCachedXmlBlockFiles;
final XmlBlock[] cachedXmlBlocks = mCachedXmlBlocks;
// First see if this block is in our cache.
final int num = cachedXmlBlockFiles.length;
for (int i = 0; i < num; i++) {
if (cachedXmlBlockCookies[i] == assetCookie && cachedXmlBlockFiles[i] != null
&& cachedXmlBlockFiles[i].equals(file)) {
return cachedXmlBlocks[i].newParser();
}
}
// Not in the cache, create a new block and put it at
// the next slot in the cache. (EVIDENCE FOR CACHING)
final XmlBlock block = mAssets.openXmlBlockAsset(assetCookie, file);
if (block != null) {
final int pos = (mLastCachedXmlBlockIndex + 1) % num;
mLastCachedXmlBlockIndex = pos;
final XmlBlock oldBlock = cachedXmlBlocks[pos];
if (oldBlock != null) {
oldBlock.close();
}
cachedXmlBlockCookies[pos] = assetCookie;
cachedXmlBlockFiles[pos] = file;
cachedXmlBlocks[pos] = block;
return block.newParser();
}
}
} catch (Exception e) {
final NotFoundException rnf = new NotFoundException("File " + file
+ " from xml type " + type + " resource ID #0x" + Integer.toHexString(id));
rnf.initCause(e);
throw rnf;
}
}
throw new NotFoundException("File " + file + " from xml type " + type + " resource ID #0x"
+ Integer.toHexString(id));
}https://stackoverflow.com/questions/45138134
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