如何在Python中实现ECDF？

Question

我正在尝试从一个paper中实现经验分布函数，在第3页有MATLAB实现。

我根据NumPy for MATLAB users documentation进行了转换，同时考虑到了statsmodels implements ECDF

from statsmodels.distributions.empirical_distribution import ECDF     

def ecdf_representation(D, n):
     """calculate ECDF from D at n points"""
     m = np.mean(D)
     X = []
     for d in xrange(D.shape[0] + 1):
         func = ECDF([D[:, d] + np.random.randn(np.shape(D[:, d])) * 0.01])
         ll = func(np.linspace(0, 1, n))
         X = [X, ll]
     X = [X, m]
     plt.plot(X)
     plt.show()
     return X

我得到了错误：

line 25, in ecdf_representation
func = ECDF([D[:, d] + np.random.randn(np.shape(D[:, d]))])
IndexError: too many indices for array

D.shape[0]不返回列数吗？所以，D[:, d]应该可以工作，对吧？这里发生了什么事？

Answer 1

D.shape将返回行，而不是列：

What does .shape[] do in "for i in range(Y.shape[0])"?

D.shape1将返回列