在Java Swing中使用invokeAndWait时出现错误

Question

我已经创建了一个从其他Java类文件调用的Swing GUI。

GUI的构造函数：

public AdviceGUI(AdviceModel model) throws InvocationTargetException, InterruptedException {

    System.out.println("I am called");

    //AdviceGUI.model= model;
    initComponents();

    try {
        for (javax.swing.UIManager.LookAndFeelInfo info : javax.swing.UIManager
                .getInstalledLookAndFeels()) {
            if ("Nimbus".equals(info.getName())) {
                javax.swing.UIManager.setLookAndFeel(info.getClassName());
                break;
            }
        }
    } catch (ClassNotFoundException ex) {
        java.util.logging.Logger.getLogger(AdviceGUI.class.getName()).log(
                java.util.logging.Level.SEVERE, null, ex);
    } catch (InstantiationException ex) {
        java.util.logging.Logger.getLogger(AdviceGUI.class.getName()).log(
                java.util.logging.Level.SEVERE, null, ex);
    } catch (IllegalAccessException ex) {
        java.util.logging.Logger.getLogger(AdviceGUI.class.getName()).log(
                java.util.logging.Level.SEVERE, null, ex);
    } catch (javax.swing.UnsupportedLookAndFeelException ex) {
        java.util.logging.Logger.getLogger(AdviceGUI.class.getName()).log(
                java.util.logging.Level.SEVERE, null, ex);
    }

    //check
    java.awt.EventQueue.invokeAndWait(new Runnable() {
        public void run() {
            try {
                new AdviceGUI(model).setVisible(true);
            } catch (InvocationTargetException | InterruptedException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

        }
    });

}

在主Java类中调用GUI的构造函数的函数：

public Map<String,ArrayList<String>> queryExpertGUI(AdviceModel model) throws InvocationTargetException, InterruptedException {
    for(String str : model.orderedQueries) {
        Utils.println("Clause:" + str);
    }

    //Modes file
    //String mode_dir =  cmdArgs.getTrainDirVal()
    System.out.println("sssssssssss"+" "+model.convertModelForBK());

    model.setUserClauses(model.convertModelForBK());
    System.out.println("ssss"+" "+model.userClauses);

    AdviceGUI a = new AdviceGUI(model);

用例是每次调用调用GUI的构造函数的函数时，在for循环中调用GUI，并在GUI中单击按钮后等待GUI(Jframe)关闭。为此，我在构造函数中使用了invokeAndWait()。但我得到以下错误：

Caused by: java.lang.Error: Cannot call invokeAndWait from the event dispatcher thread
at java.awt.EventQueue.invokeAndWait(EventQueue.java:1303)
at java.awt.EventQueue.invokeAndWait(EventQueue.java:1296)
at edu.wisc.cs.will.Boosting.UI.AdviceGUI.<init>(AdviceGUI.java:87)
at edu.wisc.cs.will.Boosting.UI.AdviceGUI$1.run(AdviceGUI.java:90)
at java.awt.event.InvocationEvent.dispatch(InvocationEvent.java:301)
at java.awt.EventQueue.dispatchEventImpl(EventQueue.java:756)
at java.awt.EventQueue.access$500(EventQueue.java:97)
at java.awt.EventQueue$3.run(EventQueue.java:709)
at java.awt.EventQueue$3.run(EventQueue.java:703)
at java.security.AccessController.doPrivileged(Native Method)
at java.security.ProtectionDomain$JavaSecurityAccessImpl.doIntersectionPrivilege(ProtectionDomain.java:76)
at java.awt.EventQueue.dispatchEvent(EventQueue.java:726)
at java.awt.EventDispatchThread.pumpOneEventForFilters(EventDispatchThread.java:201)
at java.awt.EventDispatchThread.pumpEventsForFilter(EventDispatchThread.java:116)
at java.awt.EventDispatchThread.pumpEventsForHierarchy(EventDispatchThread.java:105)
at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:101)
at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:93)
at java.awt.EventDispatchThread.run(EventDispatchThread.java:82)

对于Java新手来说，任何建议都会很有帮助。

Answer 1

看起来你在这里进行了无意的递归：

public AdviceGUI(AdviceModel model) throws InvocationTargetException, InterruptedException {
    // java.awt.EventQueue.invokeAndWait(new Runnable() { public void run() { try {
    new AdviceGUI(model).setVisible(true);
    // } catch (InvocationTargetException | InterruptedException e) { } } } });
}

AdviceGUI构造函数将尝试构造另一个AdviceGUI实例，该实例将创建另一个实例，该实例将创建另一个...

您应该重新查看是谁创建了第一个AdviceGUI实例，并在这一点上使用，使用SwingUtilities.invokeLater( new Runnable() { ... } )构造和显示UI，并从AdviceGUI构造函数中删除invokeLater。