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社区首页 >问答首页 >在r的帮助下给出不同类型变量的累计和的列

在r的帮助下给出不同类型变量的累计和的列
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Stack Overflow用户
提问于 2017-06-02 19:03:13
回答 1查看 34关注 0票数 0

我有一个看起来像这样的数据

代码语言:javascript
复制
    structure(c("Manufacturing Excell", "NPI Efficiencies", "NPI Efficiencies", 
"Manufacturing Excell", "Manufacturing Excell", "Material Efficiencie", 
"NPI Efficiencies", "Manufacturing Excell", "NPI Efficiencies", 
"NPI Efficiencies", "NPI Efficiencies", "Material Efficiencie", 
"NPI Efficiencies", "NPI Efficiencies", "Manufacturing Excell", 
"Manufacturing Excell", "NPI Efficiencies", "NPI Efficiencies", 
"NPI Efficiencies", "NPI Efficiencies", "Material Efficiencie", 
"NPI Efficiencies", "NPI Efficiencies", "NPI Efficiencies", "Manufacturing Excell", 
"NPI Efficiencies", "NPI Efficiencies", "Manufacturing Excell", 
"Manufacturing Excell", "Manufacturing Excell", "Manufacturing Excell", 
"NPI Efficiencies", "Manufacturing Excell", "Material Efficiencie", 
"Manufacturing Excell", "Manufacturing Excell", "NPI Efficiencies", 
"Manufacturing Excell", "Manufacturing Excell", "Manufacturing Excell", 
"NPI Efficiencies", "NPI Efficiencies", "Material Efficiencie", 
"NPI Efficiencies", "Manufacturing Excell", "NPI Efficiencies", 
"Manufacturing Excell", "NPI Efficiencies", "Manufacturing Excell", 
"Manufacturing Excell", "Manufacturing Excell", "NPI Efficiencies", 
"NPI Efficiencies", "Manufacturing Excell", "NPI Efficiencies", 
"NPI Efficiencies", "Manufacturing Excell", "Manufacturing Excell", 
"NPI Efficiencies", "NPI Efficiencies", "NPI Efficiencies", "NPI Efficiencies", 
"NPI Efficiencies", "NPI Efficiencies", "NPI Efficiencies", "Material Efficiencie", 
"NPI Efficiencies", "NPI Efficiencies", "NPI Efficiencies", "NPI Efficiencies", 
"Manufacturing Excell", "Manufacturing Excell", "Material Efficiencie", 
"NPI Efficiencies", "NPI Efficiencies", "Material Efficiencie", 
"Material Efficiencie", "NPI Efficiencies", "NPI Efficiencies", 
"Manufacturing Excell", "NPI Efficiencies", "NPI Efficiencies", 
"NPI Efficiencies", "Material Efficiencie", "NPI Efficiencies", 
"Material Efficiencie", "Manufacturing Excell", "Material Efficiencie", 
"NPI Efficiencies", "Manufacturing Excell", "Material Efficiencie", 
"NPI Efficiencies", "NPI Efficiencies", "NPI Efficiencies", "Manufacturing Excell", 
"Manufacturing Excell", "NPI Efficiencies", "Manufacturing Excell", 
"Material Efficiencie", "NPI Efficiencies", "Material Efficiencie", 
"NPI Efficiencies", "NPI Efficiencies", "Manufacturing Excell", 
"NPI Efficiencies", "NPI Efficiencies", "NPI Efficiencies", "NPI Efficiencies", 
"Manufacturing Excell", "Material Efficiencie", "Material Efficiencie", 
"Manufacturing Excell", "Material Efficiencie", "Manufacturing Excell", 
"Manufacturing Excell", "NPI Efficiencies", "NPI Efficiencies", 
"NPI Efficiencies", "Manufacturing Excell", "Material Efficiencie", 
"NPI Efficiencies", "NPI Efficiencies", "NPI Efficiencies", "NPI Efficiencies", 
"NPI Efficiencies", "NPI Efficiencies", "NPI Efficiencies", "Manufacturing Excell", 
"Manufacturing Excell", "NPI Efficiencies", "NPI Efficiencies", 
"NPI Efficiencies", "NPI Efficiencies", "NPI Efficiencies", "Manufacturing Excell", 
"NPI Efficiencies", "NPI Efficiencies", "NPI Efficiencies", "NPI Efficiencies", 
"Manufacturing Excell", "NPI Efficiencies", "Manufacturing Excell", 
"NPI Efficiencies", "Material Efficiencie", "NPI Efficiencies", 
"NPI Efficiencies", "Manufacturing Excell", "Manufacturing Excell", 
"Manufacturing Excell", "NPI Efficiencies", "NPI Efficiencies", 
"Material Efficiencie", "Material Efficiencie", "Material Efficiencie", 
"Material Efficiencie", "NPI Efficiencies", "NPI Efficiencies", 
"Manufacturing Excell", "Manufacturing Excell", "Manufacturing Excell", 
"Manufacturing Excell", "Manufacturing Excell", "Manufacturing Excell", 
"NPI Efficiencies", "NPI Efficiencies", "NPI Efficiencies", "Manufacturing Excell", 
"Manufacturing Excell", "Material Efficiencie", "NPI Efficiencies", 
"NPI Efficiencies", "28859", "15134", "29429", "14214", "37988", 
"15328", "42679", "46206", "43311", "8158", "29937", "6021", 
"5581", "44627", "36779", "15888", "20088", "42170", "11560", 
"16401", "30293", "27682", "44574", "20240", "10176", "45920", 
"40615", "28510", "23527", "35717", "12608", "30585", "1344", 
"30179", "38589", "18135", "32662", "577", "47836", "36944", 
"8946", "36730", "6499", "47177", "31564", "17612", "19799", 
"43469", "780", "29003", "729", "39209", "8237", "12442", "40877", 
"45338", "44977", "2081", "47886", "19948", "38960", "27127", 
"33186", "36972", "29774", "24197", "47513", "21171", "10992", 
"2630", "39740", "38639", "8373", "7932", "44641", "8877", "4256", 
"47425", "4972", "11793", "48437", "15102", "30181", "23058", 
"27086", "11750", "32797", "33320", "42980", "2712", "3360", 
"18773", "34625", "48207", "18044", "16727", "36327", "38051", 
"39081", "35858", "11747", "32221", "45342", "25444", "27538", 
"3725", "29636", "37667", "24387", "43088", "49972", "39308", 
"17497", "26198", "42199", "20640", "26455", "42792", "36511", 
"16867", "34142", "10629", "15415", "38989", "24381", "45988", 
"19603", "40886", "16616", "13004", "8370", "34725", "17915", 
"29838", "38500", "10620", "45602", "11911", "38119", "308", 
"37473", "17560", "14887", "30872", "7622", "20169", "38494", 
"12728", "14816", "37183", "18602", "157", "49615", "12902", 
"31344", "15606", "30386", "49746", "26466", "19784", "9326", 
"33639", "25323", "31404", "20045", "45788", "49454", "13271", 
"44675", "44926", "33041"), .Dim = c(171L, 2L))

现在我要做的是创建3个不同的列,让我在材料效率、NPI效率和制造效率方面累积节省。有没有办法做到这一点。我所说的列是指3个不同的列,用于不同的储蓄类型。

EN

回答 1

Stack Overflow用户

发布于 2017-06-02 19:05:48

一个选项是`

代码语言:javascript
复制
library(stringi)
stri_list2matrix(split(m1[,2], m1[,1]))

或使用base R

代码语言:javascript
复制
lst <- lapply(split(m1[,2], m1[,1]), as.numeric)
d1 <- data.frame(lapply(lst, `length<-`, max(lengths(lst))))
d1
#   Manufacturing.Excell Material.Efficiencie NPI.Efficiencies
#1                24387                 8877            44574
#2                   NA                   NA            19603
#3                   NA                   NA            29838
#4                   NA                   NA            20169

如果我们需要累加和

代码语言:javascript
复制
d1[] <- lapply(d1, function(x) cumsum(replace(x, is.na(x), 0)))
d1
#  Manufacturing.Excell Material.Efficiencie NPI.Efficiencies
#1                24387                 8877            44574
#2                24387                 8877            64177
#3                24387                 8877            94015
#4                24387                 8877           114184
票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/44327361

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