递归搜索文件

Question

我试图通过在所有子目录中传递一个目录名来查找所有文件，这意味着这个过程是递归的

myrecursive() {
  if [ -f $1 ]; then 
    echo $1
  elif [ -d $1 ]; then
    for i in $(ls $1); do
      if [ -f $1 ]; then
        echo $i 
      else
        myrecursive $i
      fi
    done
  else
    echo " sorry"
  fi
}
myrecursive $1

然而，当我用另一个目录传递目录时，我得到了2次抱歉，我哪里错了？

Answer 1

您尝试实现的目标只需使用find命令即可实现：

# will search for all files recursively in current directory 
find . * -exec echo {} \;

# will search for all *.txt file recursively in current directory 
find . -name "*.txt" -exec echo {} \;

# will search for all *.txt file recursively in current directory 
# but depth is limited to 3
find . -name "*.txt" -max-depth 3 -exec echo {} \;

有关手册，请参阅man find。How to run find -exec?

Answer 2

你的代码的问题很简单。

ls命令将返回文件名列表，但它们对于递归无效。请改用globbing。下面的循环简单地用$1/*替换了$(ls)

myrecursive() {
  if [ -f $1 ]; then 
    echo $1
  elif [ -d $1 ]; then
    for i in $1/*; do
      if [ -f $1 ]; then
        echo $i
      else
        myrecursive $i
      fi
    done
  else
    echo " sorry"
  fi
}
myrecursive $1

希望这能有所帮助

Answer 3

#!/bin/bash
myrecursive() {
  if [ -f "$1" ]; then 
    echo "$1"
  elif [ -d "$1" ]; then
    for i in "$1"/*; do
      if [ -f "$i" ]; then #here now our file is $i
        echo "$i"
      else
        myrecursive "$i"
      fi
    done
  else
    echo " sorry"
  fi
}
myrecursive "$1"