在雷达上播放信号的声音

Question

我有一个环形雷达。雷达的“手臂”以恒定的速度旋转。我需要雷达上的光点在它们通过的时候播放声音。

我如何着手解决这个问题，以确保我的每一次革命都是成功的？

(使用pygame)

我已经尝试使用if语句来捕获"arm“的(x，y)坐标和这些光点是否相等。然而，我并没有得到持续的成功。我还尝试了斜率测量和余弦测量，并检查它们在手臂和光点之间是否相等；我不能实时获得一致的成功，当有命中时，通常会在圆圈上cos相同的位置播放两个。因为手臂精确到的小数位数比光点的位置多得多，所以似乎很难用if语句很好地捕捉到它。我不知道还能怎么做。任何想法都将不胜感激！

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代码片段：

import pygame
from pygame.locals import *
import math

SIZE = 800, 800

screen = pygame.display.set_mode(SIZE, pygame.HWSURFACE | pygame.DOUBLEBUF)
done = False
bpm = 180 # based on a metronome to easily modulate speed
bbpm = 4
spm = bbpm*60/bpm
turnsPerMs = 1/(1000*spm) 
startTime = pygame.time.get_ticks()
color = Color("red")
CENTER = (400,400)
RADIUS = 200
lineLen = 100
BLACK = (0, 0, 0)
WHITE = (255, 255, 255)
RED = (255, 0, 200)
BACKGROUND = (218, 226, 235)


pygame.init()

class Blip:
    def __init__(self):
        self.mouse = (0, 0)
        self.vector = (self.mouse[0] - CENTER[0], self.mouse[1] - CENTER[1])
        self.distance = math.sqrt(self.vector[0] ** 2 + self.vector[1] ** 2)
        self.scalar = RADIUS / self.distance
        self.lineend = (int(round(CENTER[0] + self.vector[0] * self.scalar)), int(round(CENTER[1] + self.vector[1] * self.scalar)))
        self.radius = 20
        self.position = (self.lineend[0] - self.radius, self.lineend[0] + self.radius, self.lineend[1] - self.radius,
                        self.lineend[1] + self.radius)
        self.o = 255
        self.s = 200
        self.t = 150

"""def load_sound(self, filename):
        print(filename)
        self.sound = pygame.mixer.music.load(filename)"""

   def play_sound(self):
        print("Blip!")

   def draw_blip(self):
        pygame.draw.circle(screen, (100, 150, 200), self.lineend, self.radius)

class TickArm:
    def __init__(self):
    self.timeDelta = 0
    self.revDelta = 0
    self.deltaRadian = 0
    self.x = SIZE[0]/2
    self.y = SIZE[1]/2

    def draw_tickarm(self):
        self.timeDelta = pygame.time.get_ticks() - startTime
        self.revDelta = self.timeDelta*turnsPerMs;
        self.deltaRadian = self.revDelta*2*math.pi;
        self.x = CENTER[0] + math.cos(self.deltaRadian) * RADIUS
        self.y = CENTER[1] + math.sin(self.deltaRadian) * RADIUS

        # then render the line ->(x,y)
        pygame.draw.line(screen, color, CENTER, (self.x,self.y), 1)

tickarm = TickArm()
blip = Blip()

while not done:
    for e in pygame.event.get():
        if e.type == QUIT or (e.type == KEYDOWN and e.key == K_ESCAPE):
            done = True
            break

    screen.fill((BACKGROUND))
    pygame.draw.circle(screen, color, CENTER, RADIUS, 2)
    pygame.draw.circle(screen, color, CENTER, RADIUS-25, 2)
    blip.draw_blip()
    tickarm.draw_tickarm()
    pygame.display.flip()

Answer 1

没有足够的代表发表评论。抱歉的!但是你可以试试这个：

screen.get_at(x,y)

方法:将所有斑点的中心存储在一个元组center_lists中

for i in center_lists:
    if screen.get_at(i) == green:
        #play the sound

您要做的是检查每个帧上所有斑点的中心颜色。如果它们是绿色的，您可以播放声音。您甚至可以进一步创建另一个元组，为不同类型的blips创建不同的声音，并使用迭代器count i播放相应的元组。