我有一个没有故事板的iOS Webview应用程序,如何在Webview按钮点击时嵌入共享功能
网站中的html代码:共享应用程序
我想这样做:
NSString *textToShare = @"Look at this awesome website for aspiring iOS Developers!";
NSURL *myWebsite = [NSURL URLWithString:@"http://www.codingexplorer.com/"];
NSArray *objectsToShare = @[textToShare, myWebsite];
UIActivityViewController *activityVC = [[UIActivityViewController alloc] initWithActivityItems:objectsToShare applicationActivities:nil];
NSArray *excludeActivities = @[UIActivityTypeAirDrop,
UIActivityTypePrint,
UIActivityTypeAssignToContact,
UIActivityTypeSaveToCameraRoll,
UIActivityTypeAddToReadingList,
UIActivityTypePostToFlickr,
UIActivityTypePostToVimeo];
activityVC.excludedActivityTypes = excludeActivities;
[self presentViewController:activityVC animated:YES completion:nil];发布于 2017-05-24 15:10:36
如果你特别想让用户点击链接的url,那么你可以这样找到它。
- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType {
//CAPTURE USER LINK-CLICK.
NSLog(@"navigationType = %@",navigationType);
return YES;
}https://stackoverflow.com/questions/44150885
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