如何在Gradle中复制一些buildscript类路径JAR，但排除其他的？

Question

我有引用了很多JAR的buildscript块：

buildscript {
    dependencies { classpath "com.github.kulya:jmeter-gradle-plugin:1.3.4-2.13" }
    dependencies { classpath "com.eriwen:gradle-css-plugin:2.14.0" }
    dependencies { classpath "com.eriwen:gradle-js-plugin:2.14.1" }
    dependencies { classpath "com.google.javascript:closure-compiler:v20160208" }
    dependencies { classpath "org.akhikhl.gretty:gretty:+" }
}

task copyWarGradlePlugins(type: Copy) {
    destinationDir = file(project.buildDir.name + '/warGradlePlugins')

    from (buildscript.configurations.classpath)
}

我想复制(到我的WAR文件)一些引用的WAR(例如gradle-css-plugin，gradle-js-plugin的依赖项，闭包编译器)，而不是其他的(例如gretty，jmeter gradle-plugin)。

例如，我如何排除jmeter gradle-plugin及其所有依赖项？

更新：

这里有150+罐子。按文件名排除它们是不实际的，也是不可维护的。

Answer 1

buildscript {
    dependencies { classpath "com.github.kulya:jmeter-gradle-plugin:1.3.4-2.13" }
    dependencies { classpath "com.eriwen:gradle-css-plugin:2.14.0" }
    dependencies { classpath "com.eriwen:gradle-js-plugin:2.14.1" }
    dependencies { classpath "com.google.javascript:closure-compiler:v20160208" }
    dependencies { classpath "org.akhikhl.gretty:gretty:+" }
}

task copyWarGradlePlugins(type: Copy) { copy ->
    destinationDir = file(project.buildDir.name + '/warGradlePlugins')

    copy.from(buildscript.configurations.classpath) { copySpec ->
        // exclusions are based on the file name as here you will be handed
        // DefaultFileVisitDetails type
        copySpec.exclude { it.name.startsWith 'gretty' }
        copySpec.exclude { it.name.startsWith 'closure-compiler' }
    }
}