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社区首页 >问答首页 >将TapGestureRecognizer应用于水平列表中的标签- Xamarin表单

将TapGestureRecognizer应用于水平列表中的标签- Xamarin表单
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Stack Overflow用户
提问于 2017-05-03 17:45:10
回答 1查看 422关注 0票数 0

我正在尝试将一些数字的水平列表作为ListView的一项,我已经完成了,看起来很不错。

Sample screenshot of horizontal list as item in ListView

我想要的下一步是,当我滚动任何项目的水平列表时,我希望水平列表中的中间一个被自动选择,我希望所选的值显示在该项目的标签中,因此我希望其他水平列表也自动滚动并执行相同的操作(各个标签的所有值应该分别保持其偏移值的差异)。

这是一件棘手的事情,我知道GestureRecognizer在这里会有帮助,但我对在哪里以及如何在这里实现它感到困惑,因为我是xamarin新手。我将在这里编写给出上述屏幕截图的所有代码作为输出。

代码语言:javascript
复制
namespace ViewsAndComponents
 {
     class LVItem : INotifyPropertyChanged
     {
    private double _offset;
    private string _num;

    public string Num
    {
        get { return _num; }
        internal set
        {
            _num = value;
            OnPropertyChanged("Num");
        }
    }

    public double Offset
    {
        get { return _offset; }
        internal set
        {
            _offset = value;
            OnPropertyChanged("Offset");
        }
    }

    public event PropertyChangedEventHandler PropertyChanged;

    protected virtual void OnPropertyChanged(string propertyName)
    {
        PropertyChanged?.Invoke(this, new PropertyChangedEventArgs(propertyName));
    }
}

public partial class SVInsideLVItem : ContentPage
{
    ObservableCollection<LVItem> Items = new ObservableCollection<LVItem>();
    ListView timePlannerLV;

    Label tL;

    public SVInsideLVItem()
    {
        InitializeComponent();

        Items.Add(new LVItem() { Num = "label-1", Offset = 5 });
        Items.Add(new LVItem() { Num = "label-2", Offset = 1 });
        Items.Add(new LVItem() { Num = "label-3", Offset = 3 });
        Items.Add(new LVItem() { Num = "label-4", Offset = 2 });
        Items.Add(new LVItem() { Num = "label-5", Offset = 4 });

        timePlannerLV = new ListView
        {
            // Source of data items.
            ItemsSource = Items,
            HasUnevenRows = true,
            RowHeight = -1,

            //each item; it must return a Cell derivative.)
            ItemTemplate = new DataTemplate(() =>
               {

                   Label numL = new Label()
                   {
                       TextColor = Color.Black,
                       HorizontalTextAlignment = TextAlignment.Start,
                       FontSize = Device.GetNamedSize(NamedSize.Small, new Label())
                   };

                   numL.SetBinding<LVItems>(Label.TextProperty, indexer => indexer.Num);


                   List<int> items = new List<int>();
                   items.Add(1);
                   items.Add(2);
                   items.Add(3);
                   items.Add(4);
                   items.Add(5);
                   items.Add(6);
                   items.Add(7);
                   items.Add(8);
                   items.Add(9);
                   items.Add(10);
                   items.Add(11);
                   items.Add(12);
                   items.Add(13);
                   items.Add(14);
                   items.Add(15);
                   items.Add(16);
                   items.Add(17);
                   items.Add(18);
                   items.Add(19);
                   items.Add(20);

                   StackLayout sLayout = new StackLayout()
                   {
                       Orientation = StackOrientation.Horizontal,

                   };

                   for (int i = 0; i < items.Count; i++)
                   {
                       Label label = new Label()
                       {
                           HorizontalTextAlignment = TextAlignment.Center,
                           TextColor = Color.Black,
                           FontSize = Device.GetNamedSize(NamedSize.Small, new Label())
                       };

                       label.Text = items[i].ToString();

                       sLayout.Children.Add(label);
                   }

                   ScrollView scroll = new ScrollView
                   {
                       Orientation = ScrollOrientation.Horizontal,
                       Content = new StackLayout
                       {
                           Children =
                         {
                            sLayout
                           }

                       }
                   };

                   AbsoluteLayout layout = new AbsoluteLayout();
                   AbsoluteLayout.SetLayoutFlags(numL, AbsoluteLayoutFlags.All);
                   AbsoluteLayout.SetLayoutBounds(numL, new Rectangle(0.2, 0.2, 0.8, 0.25));

                   AbsoluteLayout.SetLayoutFlags(scroll, AbsoluteLayoutFlags.All);
                   AbsoluteLayout.SetLayoutBounds(scroll, new Rectangle(0.3, 0.6, 0.8, 0.2));


                   layout.Children.Add(numL);
                   layout.Children.Add(scroll);

                   return new ViewCell
                   {
                       View = new StackLayout
                       {
                           Children =
                        {
                            layout,
                            new BoxView{HeightRequest=1,BackgroundColor=Color.Gray}
                        }

                       }
                   };
               })
        };

        this.Content = new StackLayout
        {
            Children =
            {
                    timePlannerLV
            }
        };
    }

}

 }

如有任何帮助,将不胜感激..提前谢谢..

EN

回答 1

Stack Overflow用户

发布于 2017-05-03 17:49:56

我不太清楚你想在这里做什么..但您需要将手势识别器添加到您生成的标签中。所以,像这样添加它:

代码语言:javascript
复制
Label label = new Label()
{
    HorizontalTextAlignment = TextAlignment.Center,
    TextColor = Color.Black,
    FontSize = Device.GetNamedSize(NamedSize.Small, new Label())
};

label.Text = items[i].ToString();

var gestureRecognizer = new TapGestureRecognizer {
    TappedCallback = o => selectedLabel.Text = o,
    NumberOfTapsRequired = 1
};

label.GestureRecognizers.Add (gestureRecognizer);

sLayout.Children.Add(label);

希望这能帮助你和好相处。

票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/43756547

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