显示instagram发布的json结果

Question

我试着从Instagram api给出访问令牌，我用laravel用ajax发送数据，用json给access_token。我对ajax jquery的看法是：

  var $data;
    $(document).ready(function(){
        $("button").click(function(){
            $.ajax({

                method: 'POST',
                url:'https://api.instagram.com/oauth/access_token',
                headers: {'Content-Type': 'application/x-www-form-urlencoded'},
                data: {client_id: "d52c34",client_secret:"<MY client_secret HERE>",
                    grant_type:"authorization_code", redirect_uri:"http://ie-asemi.ir/laravel/public/instagram/test",
                    dataType:"json",
                    processData: true,
                    code:"{{$code}}"},
                dataType:"json",
                contentType: 'application/x-www-form-urlencoded'

        });
    });


</script>

如何在此页面中获取json结果？enter image description here

我添加了完成函数任何更改，enter image description here

Answer 1

您需要使用ajax的done方法来获取响应

var $data;
$(document).ready(function(){
     $("button").click(function(){
         $.ajax({
            method: 'POST',
            url:'https://api.instagram.com/oauth/access_token',
            headers: {'Content-Type': 'application/x-www-form-urlencoded'},
            data: {client_id: "d52c34",client_secret:"a84124d81947347fd35e9aef8",
            grant_type:"authorization_code", redirect_uri:"http://ie-asemi.ir/laravel/public/instagram/test",
            dataType:"json",
            processData: true,
            code:"{{$code}}"},
            dataType:"json",
            contentType: 'application/x-www-form-urlencoded'
      }).done(function(response) {
            console.log(response)
      });
});
</script>