该应用程序包含两个活动,FirstScreen和SecondScreen。FirstScreen包含一个NumberPicker np1和一个按钮toSecondScreen。按下按钮toSecondScreen会将应用程序转移到activity SecondScreen,其中也包含一个NumberPicker np1sc。
我试图实现的是从FirstScreen的NumberPicker np1中选择的值,并将其显示到SecondScreen的NumberPicker np2中。
到目前为止,我尝试过的方法似乎没有被正确使用。下面给出了代码和相应的错误消息。
FirstScreen.java
public class FirstScreen extends AppCompatActivity {
Button toSecondScreen;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_first_screen);
final NumberPicker np1 = (NumberPicker) findViewById(R.id.NP1);
np1.setMinValue(0);
np1.setMaxValue(5);
np1.setWrapSelectorWheel(true);
Bundle localBundle = new Bundle();
localBundle.putInt("NumPicker2Val", Integer.valueOf(np1.getValue()));
Intent localIntent = new Intent(this, SecondScreen.class);
localIntent.putExtras(localBundle);
toSecondScreen.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Intent myIntent = new Intent(v.getContext(), SecondScreen.class);
startActivityForResult(myIntent, 0);
}
});
}
}对于第二个活动,
SecondScreen.java
public class SecondScreen extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_second_screen);
final NumberPicker np1sc = (NumberPicker) findViewById(R.id.NP1SC);
np1sc.setMinValue(0);
np1sc.setMaxValue(5);
np1sc.setWrapSelectorWheel(true);
String string1 = getIntent().getStringExtra("NumPicker2Val");
np1sc.setDisplayedValues(string1);
}
}使用方法setDisplayedValues(string1)给了我一个消息:setDisplayedValues() in NumberPicker cannot be applied to (java.lang.String)我以某种方式理解了它给出的错误,但我不知道如何正确地使用这些方法。
发布于 2017-04-23 14:52:52
setDisplayedValues()方法接受字符串数组(请看here,因此您需要将string1转换为字符串数组并传递,如下所示:
np1sc.setDisplayedValues(new String[] {string1});//pass string arrayhttps://stackoverflow.com/questions/43568216
复制相似问题