PyQt4->PyQt5翻译

Question

我对表格数据的分页显示很感兴趣。我找到了这个链接:带有由PyQt4编写的有趣代码的https://sateeshkumarb.wordpress.com/2012/04/01/paginated-display-of-table-data-in-pyqt/。我试着在Python3.4上把它翻译成PyQt5。代码如下：

import sys
from PyQt5 import QtWidgets, QtCore

class Person(object):
    """Name of the person along with his city"""
    def __init__(self,name,city):
        self.name = name
        self.city = city
class PersonDisplay(QtWidgets.QMainWindow):
    def __init__(self, parent=None):
        super(PersonDisplay, self).__init__(parent)
        #QtWidgets.QMainWindow.__init__(self, parent)
        self.setWindowTitle('Person City')
        view = QtWidgets.QTableView()
        tableData = PersonTableModel()
        view.setModel(tableData)
        self.setCentralWidget(view)
        tableData.addPerson(Person('Ramesh', 'Delhi'))
        tableData.addPerson(Person('Suresh', 'Chennai'))
        tableData.addPerson(Person('Kiran', 'Bangalore'))

class PersonTableModel(QtCore.QAbstractTableModel):
    def __init__(self):
        super(PersonTableModel,self).__init__()
        self.headers = ['Name','City']
        self.persons  = ['Ramesh', 'Delhi']

    def rowCount(self,index=QtCore.QModelIndex()):
        return len(self.persons)

    def addPerson(self,person):
        self.beginResetModel()
        self.persons.append(person)
        self.endResetModel()

    def columnCount(self,index=QtCore.QModelIndex()):
        return len(self.headers)

    def data(self,index,role=QtCore.Qt.DisplayRole):
        col = index.column()
        person = self.persons[index.row()]
        if role == QtCore.Qt.DisplayRole:
            if col == 0:
                return QtWidgets.QVariant(person.name)
            elif col == 1:
                return QtWidgets.QVariant(person.city)
            return QtWidgets.QVariant()

    def headerData(self,section,orientation,role=QtCore.Qt.DisplayRole):
        if role != QtCore.Qt.DisplayRole:
            return QtWidgets.QVariant()

        if orientation == QtCore.Qt.Horizontal:
            return QtWidgets.QVariant(self.headers[section])
        return QtWidgets.QVariant(int(section + 1))

if __name__ == '__main__':
    app = QtWidgets.QApplication(sys.argv)
    appWin = PersonDisplay()
    appWin.show()
    sys.exit(app.exec_())

这看起来是正确的，但是运行停止于: view.setModel(tableData)。我不知道这是因为我的翻译还是代码错误。有什么想法吗？谢谢

Answer 1

1) QtWidgets.QVariant正在引发AttributeError，因为QVariant在QtCore包下，而不是QtWidgets下。

2)在PyQt5中你不需要显式地使用QVariant，所以你可以完全删除它们。

3)在PersonTableModel.data()中，person是一个字符串，person.name和person.city将产生一个错误。

这里是PersonTableModel的修复版本

class PersonTableModel(QtCore.QAbstractTableModel):
    def __init__(self):
        super(PersonTableModel,self).__init__()
        self.headers = ['Name','City']
        self.persons  = ['Ramesh', 'Delhi']

    def rowCount(self,index=QtCore.QModelIndex()):
        return len(self.persons)

    def addPerson(self,person):
        self.beginResetModel()
        self.persons.append(person)
        self.endResetModel()

    def columnCount(self,index=QtCore.QModelIndex()):
        return len(self.headers)

    def data(self,index,role=QtCore.Qt.DisplayRole):
        col = index.column()
        person = self.persons[index.row()]
        if role == QtCore.Qt.DisplayRole:
            if col == 0:
                return person
            elif col == 1:
                return person
            return None

    def headerData(self,section,orientation,role=QtCore.Qt.DisplayRole):
        if role != QtCore.Qt.DisplayRole:
            return None

        if orientation == QtCore.Qt.Horizontal:
            return self.headers[section]
        return int(section + 1)

P.S.

您的代码引发了此异常：

Traceback (most recent call last):
  File "test.py", line 51, in headerData
    return QtWidgets.QVariant()
AttributeError: module 'PyQt5.QtWidgets' has no attribute 'QVariant'

在问题中包括这一点可能会很有用。