如何编写一个函数来检查3个数字的组合？

Question

我目前正在制作一个双人骰子游戏，我需要创建一个函数来检查您掷出的骰子组合的值。例如:我滚动了3-4-2，我需要这个函数来检查是否有3-4-2的支出，示例滚动和他们的支出+代码如下

 //Rolling 1-1-1 would give you 5x your wager
 //Rolling 3 of the same number (except 1-1-1) would give you 2x wager
 //Rolling 3 different numbers (ex 1-4-6) would give you 1x your wager
 //Rolling 1-2-3 makes the player automatically lose a round and pay opposing Player 2x wager

    #include <iostream>
#include <string>
#include <time.h>
using namespace std;

void roll_3_dice(int &dice1, int &dice2, int &dice3) 
{
    srand(time(NULL));
    dice1 = rand() % 6 + 1;
    dice2 = rand() % 6 + 1;
    dice3 = rand() % 6 + 1;
    return;
}


int main()
{
    int cash = 90000;
    int wager; 
    int r;


    //dealer's die
    int dealer1;
    int dealer2;
    int dealer3;

    // your die
    int mdice1;
    int mdice2;
    int mdice3;


    while ( cash > 100 || round < 10 )
    {
        cout << "Set your wager: "<< endl;
        cin >> wager;

        while (wager < 100 || wager > 90000)
        {
            cout << "Minimum wager is 100; Maximum wager is 90000 ";
            cin >> wager;
        }

        cout << "You wagered: " << wager << endl;
        cout << "You have " << cash - wager << " remaining" << endl;
        cash = cash - wager;

        cout << endl;
        cout << "Dealer will now roll the dice" << endl;

        roll_3_dice(dealer1, dealer2, dealer3);

        cout << "Dealer rolled the following: " << endl;
        cout << dealer1 << "-" << dealer2 << "-" << dealer3 << endl;

        cout << "It's your turn to roll the dice." << endl;
        cout << endl; 
        cout << "Press any key to roll the dice" << endl;
        cin >> r;

        roll_3_dice(mdice1, mdice2, mdice3);

        cout << "You rolled the following: " << endl;
        cout << mdice1 << "-" << mdice2 << "-" << mdice3 << endl;

        system ("pause`enter code here`");
    }
}

Answer 1

我建议先把你的算法写在纸上，就像你在代码顶部的注释中所做的那样。

然后，问问你自己，你需要什么来处理最后的赌注？如参数中所示。例如，在您的例子中，您可能需要一个函数，该函数将初始赌注和三个骰子的值作为输入参数。

此函数将返回最终赌注。

最后，在函数本身中，按优先级规则组织算法。如果1-1-1给你5倍的赌注，那么这是一种特殊的情况，可能可以在函数的顶部隔离出来，你可以直接返回5倍的初始赌注，而不需要处理任何进一步的操作。你只需要用if语句组织不同的情况，关于每条语句的优先级。例如，1-1-1的情况必须出现在“每个骰子的相同数字”之前。

希望这能有所帮助。