我有两个问题
SELECT COUNT(DISTINCT keyword_id),
date_trunc('month', rank_date) AS date
FROM keyword_ranks, keywords
WHERE keywords.deleted_at IS NULL
AND keywords.id=keyword_ranks.keyword_id
AND keywords.business_id=27 GROUP BY date_trunc('month', rank_date);结果集是

现在我添加了一些FILTER子句,比如
SELECT COUNT(DISTINCT keyword_id) FILTER (WHERE rank>50 OR rank is null) AS "50+",
COUNT(DISTINCT keyword_id) FILTER (WHERE rank BETWEEN 21 AND 50) AS "21-50",
COUNT(DISTINCT keyword_id) FILTER (WHERE rank BETWEEN 11 AND 20) AS "11-20",
COUNT(DISTINCT keyword_id) FILTER (WHERE rank BETWEEN 4 AND 10) AS "4-10",
COUNT(DISTINCT keyword_id) FILTER (WHERE rank BETWEEN 1 AND 3) AS "1-3",
date_trunc('month', rank_date) AS date
FROM keyword_ranks, keywords
WHERE keywords.deleted_at IS NULL
AND keywords.id=keyword_ranks.keyword_id
AND keywords.business_id=27 GROUP BY date_trunc('month', rank_date);它的结果集是

从第一个查询结果可以看出,每个月的distinct keyword_id计数为147。但是,当使用FILTER子句时,为什么总数超过147?如果这不是获得不同计数的方法,那该怎么做呢?请容忍我的新手问题。任何帮助都非常感谢
发布于 2017-04-04 20:52:57
ids在一个等级中是不同的,但在总数中不是。检查此示例:
with v (id, rank) as (values (1,1),(1,10))
select
count(distinct id) as total,
count(distinct id) filter (where rank < 10) as "< 10",
count(distinct id) filter (where rank >= 10) as ">= 10"
from v
;
total | < 10 | >= 10
-------+------+-------
1 | 1 | 1使排名总和与总和匹配的唯一方法是不使用distinct。
with v (id, rank) as (values (1,1),(1,10))
select
count(id) as total,
count(id) filter (where rank < 10) as "< 10",
count(id) filter (where rank >= 10) as ">= 10"
from v
;
total | < 10 | >= 10
-------+------+-------
2 | 1 | 1https://stackoverflow.com/questions/43207453
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