Squirrel Powershell文件未创建Setup.exe

Question

我在构建服务器上运行了以下PowerShell脚本

Write-Host "Current Path  $env:Agent_BuildDirectory"
Write-Host "Build Number  $env:Build_BuildNumber"
$squirrel = "$env:BUILD_SOURCESDIRECTORY\packages\squirrel.windows.*\tools\Squirrel.exe"
$releaseDir = '.\Releases'
$nugetPackFile = ".\MyApp\MyApp.$env:Build_BuildNumber.nupkg"
Write-Host $squirrel
Write-Host $nugetPackFile

if((Test-Path $nugetPackFile) -and (Test-Path $squirrel)) {
    $squirrelArg1 = '--releasify=' + $nugetPackFile
    $squirrelArg2 = '--releaseDir=' + $releaseDir
    & $squirrel $squirrelArg1 $squirrelArg2 
}

它会运行，并且只在.\Releases文件夹中创建一个nupkg。如果我在构建服务器代理的Visual Studio实例中运行相同的--releasify命令，它将创建所有的setup.exe和Releases文件。为什么这个PowerShell脚本的工作方式与在VS的NuGet PowerShell窗口中运行的命令不同？

Answer 1

我没有玩过Squirrel，所以这可能不起作用；但这里的代码太多了，不能作为评论提交……

试试这个：

Write-Host "Current Path  $env:Agent_BuildDirectory"
Write-Host "Build Number  $env:Build_BuildNumber"
$squirrel = Get-Item (Join-Path $env:BUILD_SOURCESDIRECTORY "packages\squirrel.windows.*\tools\Squirrel.exe") | select -First 1 -Expand FullName
$releaseDir = '.\Releases'
$nugetPackFile = ".\MyApp\MyApp.$env:Build_BuildNumber.nupkg"
Write-Host $squirrel
Write-Host $nugetPackFile

if((Test-Path $nugetPackFile) -and (Test-Path $squirrel)) {
    $squirrelArg1 = "--releasify=`"$nugetPackFile`""
    $squirrelArg2 = "--releaseDir=`"$releaseDir`""
    & $squirrel $squirrelArg1 $squirrelArg2 
}

获取Squirrel.exe路径

• (Join-Path $env:BUILD_SOURCESDIRECTORY "packages\squirrel.windows.*\tools\Squirrel.exe") -在这里，我使用Join-Path来避免任何有关path的值是否以asterisk/wildcard).
• | select -First 1 -Expand FullName结尾的问题-我将此放在该路径之前，以便它将该路径解析为有效路径(即找出asterisk/wildcard).
• | select -First 1 -Expand FullName的任何匹配项，然后添加此内容以获得与结果匹配的第一个路径，并向squirrel.exe

返回完整的文件路径

传递参数

对于下面的语句，我在路径两边添加了双引号；有时这是为了澄清它们与哪个参数相关；特别是当路径中有任何空格或特殊字符时。我还从使用+切换到将变量放在双引号中，因为这样可以更容易地连接字符串中的引号。我在字符串中的引号上使用了反引号来转义这些字符。

• $squirrelArg1 = "--releasify=`"$nugetPackFile`""
• $squirrelArg2 = "--releaseDir=`"$releaseDir`""

希望这能有所帮助，但遗憾的是，这只是我的猜测；抱歉。

更新

获取最新版本；假设路径中的星号packages\squirrel.windows.*\tools\Squirrel.exe以以下形式表示版本号：Major.Minor.Build.

$squirrel = Get-Item (Join-Path $env:BUILD_SOURCESDIRECTORY "packages\squirrel.windows.*\tools\Squirrel.exe") | %{
    if ($_ -match '.*\\squirrel\.windows\.(?<Major>\d+)\.(?<Minor>\d+)\.(?<Build>\d+)\\tools\\Squirrel\.exe') {
        (new-object -TypeName PSObject -Property $matches)
    }
} | sort @{e={$_.Major};a=0}, @{e={$_.Minor};a=0}, @{e={$_.Build};a=0} | select -First 1 -ExpandProperty '0'

Answer 2

我找到了答案here

Write-Host "Current Path  $env:Agent_BuildDirectory"
Write-Host "Build Number  $env:Build_BuildNumber"

$squirrel = Get-Item (Join-Path $env:BUILD_SOURCESDIRECTORY "packages\squirrel.windows.*\tools\Squirrel.exe") | %{
if ($_ -match '.*\\squirrel\.windows\.(?<Major>\d+)\.(?<Minor>\d+)\.(?<Build>\d+)\\tools\\Squirrel\.exe') {
    (new-object -TypeName PSObject -Property $matches)
    }
} | sort @{e={$_.Major};a=0}, @{e={$_.Minor};a=0}, @{e={$_.Build};a=0} | select -First 1 -ExpandProperty '0'

Set-Alias Squirrel $squirrel

$releaseDir = '.\Releases'
$nugetPackFile = ".\MyApp\MyApp.$env:Build_BuildNumber.nupkg"
Write-Host $squirrel
Write-Host $nugetPackFile

if((Test-Path $nugetPackFile) -and (Test-Path $squirrel)) {
    Squirrel --releasify $nugetPackFile --releaseDir $releaseDir | Write-Output
}

非常感谢@JohnLBevan帮助修复我的powershell代码。