如何让google api免费翻译成json格式返回？

Question

我想为我的chrome扩展使用免费的谷歌翻译api。

网址：https://translate.googleapis.com/translate_a/single?client=gtx&sl=en&tl=hi&dt=t&dt=t&q=hello

以数组格式返回f.txt文件。

[[["नमस्ते","hello",,,1]],,"en"]

我目前正在使用Yandex翻译作为我的扩展。Yandex以JSON格式返回它。https://translate.yandex.net/api/v1.5/tr.json/translate?key=trnsl.1.1.20170222T005237Z.c822f17f30208ee9.7df12d4944735ac8d985d500634196b9155dcbc0&text=hello&lang=hi

{"code":200,"lang":"en-hi","text":["नमस्कार"]}

所以，有没有什么办法，我可以得到上述免费的谷歌翻译api。

Answer 1

请使用下面的柱塞代码来翻译JSON对象。您可以在相应语言的代码中更改源和目标。https://embed.plnkr.co/87eEqc/

然后可以使用https://jsonformatter.curiousconcept.com/对JSON进行格式化。

链接中的示例代码片段

$scope.method = 'POST';
$scope.url = 'https://translation.googleapis.com/language/translate/v2? 
key=AIzaSyA1bHYc3VOCxotWBY5T61z31C91xgl4Kck';
$scope.data = {
        "q" :"Search",
        "source": "en",
        "target": "es"   
    };
  $scope.header =   {'Content-Type': 'application/json'};

  $scope.test = function() {
    var source = {
    "header": {
      "Home": "Home",
      "Join": "Join",
      "Login": "Login",
      "Favorites": "Favorites",
      "Signout": "Signout",
      "Hi": "Hi",
      "Wishlist": "Wishlist",
      "Cart": "Cart",
      "Search": "Search"
    },
  }
   $scope.sourceArray = source;
  angular.forEach(source, function(value, key) {
    var outerObjKey = key;
    var outerArr= source[key];
     angular.forEach(outerArr, function(value, key) {

              var innerObjKey = key;
                var data = {
            "q" :value,
            "source": "en",
            "target": "es"   
        };
        $scope.fetch(data,outerObjKey,innerObjKey,source)
     })

  });
}


 $scope.fetch = function(dataToChange,outerKey,innerKey,scrArr) {
$http({method: $scope.method, url: $scope.url,data:dataToChange,headers:$scope.header})
  .success(function(data, status) {
    $scope.status = status;
    $scope.sourceArray[outerKey][innerKey] = data.data.translations[0].translatedText;
    console.log(JSON.stringify($scope.sourceArray));
    $scope.jsonString = JSON.stringify($scope.sourceArray);
  })
  .error(function(data, status) {
    $scope.status = status;
    $scope.data = "Request failed";
});
};