TypeError: semrush.backlinks_refdomains不是函数

Question

伙计们，当我试图使用backlinks_refdomains和backlinks_refips从SEMRUSH API https://www.semrush.com/api-analytics/#domain_rank中获取数据时，它显示了这个错误。

当我调用相同的函数domain_rank时，它以json格式响应我。你能帮我解决这个问题吗。附加的图像是结果，当是给我domain_rank，但没有其他因素，如baclinks等。我正在使用这个代码。

`

module.exports = {
index: function(req,res){

    console.log("Hello welocme!");
    var SEMRushAPI = require('sails-semrush');
    var URL = "www.flipkart.com";
    var database = {database:'us'};
    var semrush = new SEMRushAPI('XXXXXXXXXXXXXXX');

semrush.backlinks(URL, database, function(err, response){
if (err){

        console.log("There is some error to fetching web traffic on API !");
        console.log("err: ",err);
        console.log("There is some error to fetching web traffic on API !");
        }else{
                 console.log("backlinks");
            console.log(" Response: ",response);
            console.log("**************** Get the web traffic successfully ***************");
            console.log("******zone, country, ip*******");
        } 

semrush.backlinks_refdomains(URL, database, function(err, response){ 
          if (err){

        console.log("There is some error to fetching web traffic on API !");
        console.log("err: ",err);
        console.log("There is some error to fetching web traffic on API !");
        }else{

console.log("domain_score_asc, domain_score_desc, backlinks_asc, backlinks_desc, last_seen_asc, last_seen_desc, first_seen_asc, first_seen_desc");
console.log(" Response: ",response);
console.log("**************** Get the web traffic successfully **************");
console.log("zone, country, ip");
}
});

`

This is image of my output, where i getting domain ranks but not backlinks can some one help me in this

提前感谢！！

Answer 1

您是否尝试对函数使用close ()？

有漏掉的括号')'：

1) semrush.backlinks(URL，数据库，函数(错误，响应){

尝试修复它: semrush.backlinks(URL，database，function(err，response)){

2) semrush.backlinks_refdomains(URL，数据库，函数(错误，响应){

尝试修复它: semrush.backlinks_refdomains(URL，database，function(err，response)){