如何将过期日期添加到jwt-simple token

Question

apiRoutes.post('/authenticate', function(req, res) {
  User.findOne({
    name: req.body.name
  }, function(err, user) {
    if (err) throw err;

    if (!user) {
      res.send({success: false, msg: 'Authentication failed. User not found.'});
    } else {
      // check if password matches
      user.comparePassword(req.body.password, function (err, isMatch) {
        if (isMatch && !err) {
          // if user is found and password is right create a token
          var expires=moment().add(1,'days').valueOf();
          var token = jwt.encode(user, config.secret,{
          exp: expires});
          // return the information including token as JSON
          res.json({success: true, token: 'JWT ' + token});
        } else {
          res.send({success: false, msg: 'Authentication failed. Wrong password.'});
        }
      });
    }
  });
});

It提示错误: /home/oracle/node/ang_backend1/node_modules/jwt-simple/lib/jwt.js:130抛出新错误(‘算法不受支持’)；^

错误:位于/home/oracle/node/ang_backend1/app.js:198:27 at /home/oracle/node/ang_backend1/app/models/user.js:48:9 at /home/oracle/node/ang_backend1/node_modules/bcryptjs/dist/bcrypt.js:261:17 at /home/oracle/node/ang_backend1/node_modules/bcryptjs/dist/bcrypt.js:1198:21的Object.jwt_encode as encode不支持算法在processImmediate as _immediateCallback的Immediate.next as _onImmediate

Answer 1

我认为你没有得到令牌，你应该这样做：

var expires=moment().add(1,'days').valueOf();
          var token = jwt.encode(user, config.secret,{
          exp: expires}),app.get('jwtTokenSecret'));

Answer 2

您的安全路由应定义为：

router.get('/enums', passport.authenticate('jwt', {session: false}), async (req, res) => { ...

const passport = require('passport')在哪里。

为了向令牌添加过期时间，您必须设置两个参数(以秒为单位)：exp和nbf，如下所示：

let expires = (Date.now() / 1000) + 60 * 30
let nbf = Date.now() / 1000

let token = await jwt.encode({nbf: nbf, exp: expires, id: user_id}, jwtSecret).

where const jwt = require('jwt-simple')