Android: Sort JSON

Question

不熟悉使用REST API和JSON文件，但我已经从一个天气API中检索了有关我当前位置的天气条件的数据。JSON文件包含数据，例如我的位置、天气速度等。我希望将所有这些单独的数据部分排序到textViews中，以便可以清楚地看到它们。

我的异步类：

import android.app.Activity;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.os.AsyncTask;
import java.util.ArrayList;
import android.widget.*;
import java.util.Date;
import android.util.Log;

public class RESTAPI extends Activity {

ArrayList<String> items = new ArrayList<String>();
// json test string
String jsonTest;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_restapi);
    // start the  AsyncTask for calling the REST service using httpConnect class
    new AsyncTaskParseJson().execute();
}


// added asynctask class methods below -  you can make this class as a separate class file
public class AsyncTaskParseJson extends AsyncTask<String, String, String> {

    // set the url of the web service to call
    String yourServiceUrl = "http://api.apixu.com/v1/current.json?key=e87e62510df946cc84c02652162112&q=LN11RX";

    @Override

    protected void onPreExecute() {
    }

    @Override

    protected String doInBackground(String... arg0) {

        try {
            // create new instance of the httpConnect class
            httpConnect jParser = new httpConnect();

            // get json string from service url
            String json = jParser.getJSONFromUrl(yourServiceUrl);

            // save returned json to your test string
            jsonTest = json.toString();

        } catch (Exception e) {
            e.printStackTrace();
        }
        return null;
    }

    @Override
    protected void onPostExecute(String strFromDoInBg) {
        TextView tv1 = (TextView) findViewById(R.id.jsontext);
        tv1.setText(jsonTest);
    }

}

}

我的处理网址的httpConnect类：

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import android.util.Log;


public class httpConnect {

final String TAG = "JsonParser.java";

static String json = "";

public String getJSONFromUrl(String url) {

    try {

        URL u = new URL(url);
        HttpURLConnection restConnection = (HttpURLConnection) u.openConnection();
        restConnection.setRequestMethod("GET");
        restConnection.setRequestProperty("Content-length", "0");
        restConnection.setUseCaches(false);
        restConnection.setAllowUserInteraction(false);
        restConnection.setConnectTimeout(10000);
        restConnection.setReadTimeout(10000);
        restConnection.connect();
        int status = restConnection.getResponseCode();

        // switch statement to catch HTTP 200 and 201 errors
        switch (status) {
            case 200:
            case 201:

                BufferedReader br = new BufferedReader(new InputStreamReader(restConnection.getInputStream()));

                // create a new string builder to store json data returned from the REST service
                StringBuilder sb = new StringBuilder();
                String line;

                // loop through returned data line by line and append to stringbuilder 'sb' variable
                while ((line = br.readLine()) != null) {
                    sb.append(line+"\n");
                }
                br.close();

                try {
                    json = sb.toString();
                } catch (Exception e) {
                    Log.e(TAG, "Error parsing data " + e.toString());
                }
                return json;
        }
        // HTTP 200 and 201 error handling from switch statement
    } catch (MalformedURLException ex) {
        Log.e(TAG, "Malformed URL ");
    } catch (IOException ex) {
        Log.e(TAG, "IO Exception ");
    }
    return null;
}

那么有没有办法对返回的数据进行排序，并将每一位数据放入它自己的文本框中呢？

JSON截图：

​

​

Answer 1

如果我正确理解了您的问题，请尝试使用此link。如果我误解了，请让我知道，我会试着用另一种方法来帮助你。

编辑:大致是另一种动态创建新TextView和设置数据的方法：

TextView view;
LinearLayout currLayout = (LinearLayout) findViewById(R.id.LinearLayout);
for(String value : items) {
    view = new TextView();
    view.setText(value);
    currLayout.addView(view);
}

Answer 2

• 为您获得的响应创建pojo类：

像这样打开任何转换站点：-

http://www.jsonschema2pojo.org/

• 在这里粘贴json响应，然后单击zip，所有的pojo类都将自动为您创建。

现在，在您的代码中执行以下操作

protected String doInBackground(String... arg0) {

        try {
            // create new instance of the httpConnect class
            httpConnect jParser = new httpConnect();

            // get json string from service url
            String json = jParser.getJSONFromUrl(yourServiceUrl);

            // save returned json to your test string
            jsonTest = json.toString();
Gson gson = new Gson();
/*here Example class is the main pojo class, you can use this class which will be there in the zip, which is created from jsontoPojo converting site */

Example  response = gson.fromJson(json, Example.class);

/*
 *Now to get data 
 * just do this */

String name = getLocation().getName();
.
.
.


        } catch (Exception e) {
            e.printStackTrace();
        }
        return null;
    }

有关详细信息，请查看此示例，example of data parsing using gson

并且您还需要在build.gradle文件中添加此依赖项

compile 'com.google.code.gson:gson:2.4'