我有一个安卓应用程序的注册表,其中包括一个用户名和密码。我希望,当用户单击注册表单的提交按钮,然后用户名和密码将被保存到一个网络数据库(mySql数据库)。
当用户按下submit按钮时,就会执行sendPostRequest(givenUsername, givenPassword);。
sendPostRequest()函数是这样的
private void sendPostRequest(String givenUsername, String givenPassword) {
class SendPostReqAsyncTask extends AsyncTask<String, Void, String>{
@Override
protected String doInBackground(String... params) {
String paramUsername = params[0];
String paramPassword = params[1];
System.out.println("*** doInBackground ** paramUsername " + paramUsername + " paramPassword :" + paramPassword);
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost("http://10.0.2.2/imon.php");
BasicNameValuePair usernameBasicNameValuePair = new BasicNameValuePair("paramUsername", paramUsername);
BasicNameValuePair passwordBasicNameValuePAir = new BasicNameValuePair("paramPassword", paramPassword);
List<NameValuePair> nameValuePairList = new ArrayList<NameValuePair>();
nameValuePairList.add(usernameBasicNameValuePair);
nameValuePairList.add(passwordBasicNameValuePAir);
try {
UrlEncodedFormEntity urlEncodedFormEntity = new UrlEncodedFormEntity(nameValuePairList);
httpPost.setEntity(urlEncodedFormEntity);
try {
HttpResponse httpResponse = httpClient.execute(httpPost);
InputStream inputStream = httpResponse.getEntity().getContent();
InputStreamReader inputStreamReader = new InputStreamReader(inputStream);
BufferedReader bufferedReader = new BufferedReader(inputStreamReader);
StringBuilder stringBuilder = new StringBuilder();
String bufferedStrChunk = null;
while((bufferedStrChunk = bufferedReader.readLine()) != null){
stringBuilder.append(bufferedStrChunk);
}
return stringBuilder.toString();
} catch (ClientProtocolException cpe) {
System.out.println("First Exception caz of HttpResponese :" + cpe);
cpe.printStackTrace();
} catch (IOException ioe) {
System.out.println("Second Exception caz of HttpResponse :" + ioe);
ioe.printStackTrace();
}
} catch (UnsupportedEncodingException uee) {
System.out.println("An Exception given because of UrlEncodedFormEntity argument :" + uee);
uee.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
if(result.equals("working")){
Toast.makeText(getApplicationContext(), "HTTP POST is working...", Toast.LENGTH_LONG).show();
}else{
Toast.makeText(getApplicationContext(), "Invalid POST req...", Toast.LENGTH_LONG).show();
}
}
}
SendPostReqAsyncTask sendPostReqAsyncTask = new SendPostReqAsyncTask();
sendPostReqAsyncTask.execute(givenUsername, givenPassword);
}我的imon.php是这样的:
<?php
$varUsername = $_POST['paramUsername'];
$varPassword = $_POST['paramPassword'];
if($varUsername != "" && $varPassword != ""){
$con = mysql_connect('localhost', 'root', '');
if (!$con) {
die('Not connected : ' . mysql_error());
}
// make foo the current db
$db_selected = mysql_select_db('post_db', $con);
if (!$db_selected) {
die ('Can\'t use foo : ' . mysql_error());
}
$sql="INSERT INTO post_table (username,password)
VALUES
('$varUsername ','$varPassword')";
if (!mysql_query($con,$sql))
{
die('Error: ' . mysql_error($con));
}
echo 'working';
}else
{
echo 'invalid';
}
?>但是数据不会插入到my-sql数据库中。
我说错了什么??如何将报名表的数据插入web数据库??
发布于 2013-07-12 16:38:20
你不能这么做
mysql_connect('localhost', 'root', '');然后这样做
if (!mysqli_query($con,$sql))mysql和mysqli是单独的扩展。您不能与另一个共享资源。
mysqli_query()和mysql_query()的参数顺序不同。mysql_query()的第一个参数是查询。其中,在mysqli_query中,第一个参数是连接资源。您之前也混合了这两种连接。
https://stackoverflow.com/questions/17610527
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