问图形无法正确重新加载到D3强制布局中
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Stack Overflow用户

提问于 2013-07-17 11:41:54

回答 1查看 176关注 0票数 1

我在玩D3，并制作了力有向图。我想要清除并重新加载图形，以响应单击按钮。但是，当我重新加载一个已经加载的图表时，该图表的格式不正确。这是我使用的代码：

<!DOCTYPE html>
<meta charset="utf-8">
<script src="http://d3js.org/d3.v2.js?2.9.1"></script>
<style>

.link {
  fill: none;
  stroke: #666;
  stroke-width: 1.5px;
}

.node circle {
  fill: #ccc;
  stroke: #fff;
  stroke-width: 1.5px;
}

text {
  font: 10px sans-serif;
  pointer-events: none;
}

</style>
<body>
<script>

var all = [
{source: "Tockwotton", target: "List", type: "woodworking"},
{source: "Tockwotton", target: "Prince Lab", type: "woodworking"},
{source: "Prince Lab", target: "Prince Lab", type: "metalworking"},
{source: "Tockwotton", target: "List", type: "cnc"},
{source: "Granoff", target: "Prince Lab", type: "3d-printing"},
{source: "Tockwotton", target: "List", type: "drafting"},
{source: "List", target: "Prince Lab", type: "welding"},
{source: "Prince Lab", target: "Prince Lab", type: "sand-blaster"},
{source: "Tockwotton", target: "List", type: "finishing"},
{source: "Tockwotton", target: "Prince Lab", type: "finishing"},
{source: "Tockwotton", target: "Tockwotton", type: "laser-cutter"}
];

var wood = [
{source: "Tockwotton", target: "List", type: "woodworking"},
{source: "Tockwotton", target: "Prince Lab", type: "woodworking"}
];

var metal = [
{source: "Prince Lab", target: "Prince Lab", type: "metalworking"}
];

var cnc = [
{source: "Tockwotton", target: "List", type: "cnc"}
];

var print = [
{source: "Granoff", target: "Prince Lab", type: "3d-printing"}
];

var draft = [
{source: "Tockwotton", target: "List", type: "drafting"}
];

var weld = [
{source: "List", target: "Prince Lab", type: "welding"}
];

var sand = [
{source: "Prince Lab", target: "Prince Lab", type: "sand-blaster"}
];

var finishing = [
{source: "Tockwotton", target: "List", type: "finishing"},
{source: "Tockwotton", target: "Prince Lab", type: "finishing"}
];

var laser = [
{source: "Tockwotton", target: "Tockwotton", type: "laser-cutter"}
];

function render(linkdata){  

d3.selectAll("svg").remove();

links = linkdata;

nodes = {};

// Compute the distinct nodes from the links.
links.forEach(function(link) {
  link.source = nodes[link.source] || (nodes[link.source] = {name: link.source, type: link.type});
  link.target = nodes[link.target] || (nodes[link.target] = {name: link.target, type: link.type});
});

width = 960,
    height = 500;

force = d3.layout.force()
    .nodes(d3.values(nodes))
    .links(links)
    .size([width, height])
    .linkDistance(60)
    .charge(-300)
    .on("tick", tick)
    .start();

svg = d3.select("body").append("svg")
    .attr("width", width)
    .attr("height", height);

link = svg.selectAll(".link")

    .data(force.links())
    .enter().append("line")
    .attr("class", "link");

node = svg.selectAll(".node")
    .data(force.nodes())
  .enter().append("g")
    .attr("class", "node")
    .on("mouseover", mouseover)
    .on("mouseout", mouseout)
    .call(force.drag);

node.append("circle")
    .attr("r", 8);

node.append("text")
    .attr("x", 12)
    .attr("dy", ".35em")
    .text(function(d) { return d.name; });

function tick() {
  link
      .attr("x1", function(d) { return d.source.x; })
      .attr("y1", function(d) { return d.source.y; })
      .attr("x2", function(d) { return d.target.x; })
      .attr("y2", function(d) { return d.target.y; });

  node
      .attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; });
}

function mouseover() {
  d3.select(this).select("circle").transition()
      .duration(750)
      .attr("r", 16);
}

function mouseout() {
  d3.select(this).select("circle").transition()
      .duration(750)
      .attr("r", 8);
}
}
</script>

<div id="nav">
    <div id="wood">
        <a onclick="render(wood)">Woodworking</a>
    </div>
    <div id="metal">
        <a onclick="render(metal)">Metalworking</a>
    </div>
    <div id="cnc">
        <a onclick="render(cnc)">CNC</a>
    </div>
    <div id="print">
        <a onclick="render(print)">3D Printing</a>
    </div>
    <div id="draft">
        <a onclick="render(draft)">Drafting</a>
    </div>
    <div id="weld">
        <a onclick="render(weld)">Welding</a>
    </div>
    <div id="sand">
        <a onclick="render(sand)">Sand Blast</a>
    </div>
    <div id="finishing">
        <a onclick="render(finishing)">Finishing</a>
    </div>
    <div id="laser">
        <a onclick="render(laser)">Laser Cutting</a>
    </div>
    <div id="all">
        <a onclick="render(all)">All</a>
    </div>
</div>

</body>

Try it并注意，第一次单击一个项目时，它工作得很好，但如果再次单击它，您只会得到一个名为[object Object]的节点。为什么会出现这种情况?我该如何解决？

javascript

d3.js

force-layout

回答 1

Stack Overflow用户

回答已采纳

发布于 2013-07-17 12:37:44

当您使用links = linkdata时，它可能不会执行您所期望的操作。与其他一些语言一样，这不会复制数据；相反，它只是让links指向linkdata所指向的相同位置。当您循环遍历links，将它们修改为彼此指向时，您就是在修改数组中的原始对象。当您再次遍历它们时，它们已经被修改，导致您正在经历的不受欢迎的行为。

为了避免这种情况，您需要在修改数组之前对其进行深度复制。虽然有quite a few ways to do that，但您需要确保所使用的任何解决方案都会将数组克隆为数组，而不是将其转换为普通的Object。

票数 1

页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持

原文链接：

https://stackoverflow.com/questions/17690703

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