将动态值传递给php并获取日期

Question

var dt = 6;
var dtyp = M;

需要将这个值传递给php中的strtotime以获得6个月后的日期if dtyp = D需要将6天添加到当前日期，if dtyp = Y需要将6年添加到当前日期。

<?php echo date("d/m/Y", strtotime("+6 days"));?> 

$.each(data.response.duration,function(a,b){
    var dt = b.exp_dur;
    var dtyp = b.exp_type;
    $('.after_dat').val('<?php echo date("d/m/Y", strtotime("+.'dt'. days"));?>')
});

dt和dtyp将是从db动态获取的。

Answer 1

                             if(b.exp_type === 'D'){
                                $('.after_dat').val('');
                                var date = new Date();
                                futr =  parseInt(b.exp_dur)
                                date.setDate(date.getDate() +futr);
                                var dateMsg = date.getDate()+'/'+ (date.getMonth()+1) +'/'+date.getFullYear();
                                // alert(dateMsg);
                                $('.after_dat').val(dateMsg);
                            }
                            if(b.exp_type === 'M'){
                                $('.after_dat').val('');
                                futr =  parseInt(b.exp_dur)
                                var jan312009 = new Date();
                                var eightMonthsFromJan312009 = new Date(new Date(jan312009).setMonth(jan312009.getMonth()+futr));
                                var dateMsg = eightMonthsFromJan312009.getDate()+'/'+ (eightMonthsFromJan312009.getMonth()+1) +'/'+eightMonthsFromJan312009.getFullYear();
                                $('.after_dat').val(dateMsg);

                            }
                            if(b.exp_type === 'Y'){
                                $('.after_dat').val('');
                                futr =  parseInt(b.exp_dur)
                                var jan312009 = new Date();
                                var eightMonthsFromJan312009 = new Date(new Date(jan312009).setFullYear(jan312009.getFullYear()+futr));
                                var dateMsg = eightMonthsFromJan312009.getDate()+'/'+ (eightMonthsFromJan312009.getMonth()+1) +'/'+eightMonthsFromJan312009.getFullYear();
                                $('.after_dat').val(dateMsg);

                            }