我正在开发一个在线游戏网站,我想要实现的是,当我玩一个游戏时,我想在同一个页面上显示所有与当前玩的游戏类别相关的游戏。例如:我正在玩id =4的游戏,该游戏的类别为= 3。我想要显示与类别3相关的所有游戏。以此类推。谢谢
CREATE TABLE IF NOT EXISTS `jogos` (
`idGames` int(11) NOT NULL AUTO_INCREMENT,
`strNome` varchar(100) DEFAULT NULL,
`intCategoria` int(11) DEFAULT NULL,
$varCategoria_GameData = "0";
if (isset($_GET["cat"])) {
$varCategoria_GameData = $_GET["cat"];
}
mysql_select_db($database_gameconnection, $gameconnection);
$query_GameData = sprintf("SELECT * FROM jogos WHERE jogos.intCategoria = %s", GetSQLValueString($varCategoria_GameData, "int"));
$GameData = mysql_query($query_GameData, $gameconnection) or die(mysql_error());
$row_GameData = mysql_fetch_assoc($GameData);
$totalRows_GameData = mysql_num_rows($GameData);
if (!isset($_SESSION)) {
session_start();
}?>发布于 2013-07-08 10:52:13
这个怎么样?
SELECT * FROM jogos WHERE intCategoria =
( SELECT intCategoria FROM jogos WHERE idGames = $currentGameId )其中$currentGameId是正在玩的游戏的id。
https://stackoverflow.com/questions/17518523
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