我在backbone中有一个应用程序,我从服务器获取数据,然后返回给我有关酒店的数据。每家酒店可以容纳许多房间(单人间、双人间、三人间……)。为此,我创建了两个json hotel.json:
[
{
"id": "1",
"name": "Hotel1"
},
{
"id": "2",
"name": "Hotel2"
},
{
"id": "3",
"name": "Hotel3"
}
]rooms.json
[
{
"room" : [
{
"id" : "r1",
"hotel_id" : "1",
"name" : "Singola",
}
]
},
{
"room" : [
{
"id" : "r1_1",
"hotel_id" : "1",
"name" : "Doppia",
}
]
},
{
"room" : [
{
"id" : "r2",
"hotel_id" : "2",
"name" : "Singola",
}
]
},
{
"room" : [
{
"id" : "r2_1",
"hotel_id" : "2",
"name" : "Tripla",
}
]
},
]在rooms.json中,有一个名为hotel_id的字段,用于将房间链接到其酒店。这是我在backbone中查看酒店的应用程序:
var Hotel = Backbone.Model.extend({
defaults: function() {
return {
name: 'HOTEL NAME',
star: '5'
}
}
});
var HotelsCollection = Backbone.Collection.extend({
model: Hotel,
url: "includes/test-data.json",
initialize: function(){
console.log("Collection Hotel initialize");
},
parse: function(response){
return(response);
}
});
var HotelView = Backbone.View.extend({
template: _.template($("#hotel-list-template").html()),
initialize: function(){
this.collection = new HotelsCollection();
this.collection.bind('sync', this.render, this);
this.collection.fetch();
},
render: function(){
console.log('Data hotel is fetched');
var element = this.$el;
element.html('');
$(this.el).html(this.template({hotel: this.collection.models}));
}
});这是我在uderscore中的模板:
<script type="text/template" id="hotel-list-template">
<% _.each(hotel, function(name) { %>
<div id="hotel-container-<%= name.attributes.id %>">
<p>Nome Hotel: <%= name.attributes.name %></p>
</div>
<% }); %>
</script>现在,我如何将每个房间插入到同一div中的酒店中?我想做一个经典的模型,一个获取数据的集合,但是在渲染的视图中,我如何告诉backbone只将带有hotel_id=1的房间插入到id=hotel container-1的div中?
var Hotel = Backbone.Model.extend({
defaults: function() {
return {
name: 'HOTEL NAME',
star: '5'
}
}
});
var HotelsCollection = Backbone.Collection.extend({
model: Hotel,
url: "includes/test-data.json",
initialize: function(){
console.log("Collection Hotel initialize");
},
parse: function(response){
return(response);
},
getRooms : function() {
return _.map(allRooms.where({"hotel_id" : this.get("id")}), function(room) {
return room.toJSON();
});
},
addRoom : function(room) {
room.set("hotel_id", this.get("id"));
allRooms.add(room);
},
// this will return Backbone´s native toJSON Object
// with an extra field "rooms" which you can access
toJSON : function() {
var parent = Backbone.Collection.prototype.toJSON.call(this);
return _.extend({}, parent, {rooms : this.getRooms().toJSON()});
}
});
var HotelView = Backbone.View.extend({
template: _.template($("#hotel-list-template").html()),
initialize: function(){
this.collection = new HotelsCollection();
this.collection.bind('sync', this.render, this);
this.collection.fetch();
},
render: function(){
console.log('Data hotel is fetched');
var viewModel = this.collection.toJSON();
this.$el.html(this.template({models:viewModel}));
}
});
var Room = Backbone.Model.extend();
var Rooms = Backbone.Collection.extend({model:Room});
var allRooms = new Rooms();
var hotelView = new HotelView({
el: $("#hotel")
});发布于 2013-07-01 17:11:54
我建议我们在项目架构中添加一些更改。首先,我们需要像这样改变hotel模型:
{
"id": "1",
"name": "Hotel1",
"rooms": []
} 其次是模型和集合:
var Room = Backbone.Model.extend();
var Rooms = Backbone.Collection.extend({
model:Room,
url : "rooms.json"
});
var Hotel = Backbone.Model.extend({});
var HotelCollection = Backbone.Collection.extend({
model: Hotel,
url: "includes/test-data.json",
initialize: function(){
console.log("Collection Hotel initialize");
},
parse: function(response) {
response.rooms = new Rooms(response.rooms);
return response;
}
});第三个视图:
var HotelView = Backbone.View.extend({
template: _.template($("#hotel-list-template").html()),
initialize: function(){
this.collection = new HotelCollection();
this.collection.bind('sync', this.render, this);
this.collection.fetch();
},
render: function(){
console.log('Data hotel is fetched');
bindRoomToHotel();
var element = this.$el;
element.html('');
$(this.el).html(this.template({hotel: this.collection.models}));
},
bindRoomToHotel: function() {
allRooms = new Rooms();
allRooms.fetch();
_.each(this.collection.models, function(hotel) {
rooms = allRooms.where({'hotel_id' : hotel.id});
//
currentHotelRooms = hotel.get('rooms');
currentHotelRooms.add(rooms);
// or You can write like
// hotel.get('rooms').add(rooms);
}
}
});
var hotelView = new HotelView({
el: $("#hotel")
});我想这就是全部了。我希望它能帮助你
发布于 2013-07-01 06:47:26
首先,您丢失了一个Room Model和一个Room Collection,然后,您应该在所有房间的某个地方拥有一个实例。
var Room = Backbone.Model.extend();
var Rooms = Backbone.Collection.extend({
model:Room,
url : "rooms.json"
});
var allRooms = new Rooms();在这里之前非常简单。
不,您将为您的酒店模型创建一些方法,您将为您的房间启用一些操作
var Hotel = Backbone.Model.extend({
getRooms : function() {
return _.map(allRooms.where({"hotel_id" : this.get("id")}), function(room) {
return room.toJSON();
});
},
addRoom : function(room) {
room.set("hotel_id", this.get("id"));
allRooms.add(room);
},
// this will return Backbone´s native toJSON Object
// with an extra field "rooms" which you can access
toJSON : function() {
var parent = Backbone.Model.prototype.toJSON.call(this);
return _.extend({}, parent, {rooms : this.getRooms().toJSON()});
}
});
var HotelsCollection = Backbone.Collection.extend({
model: Hotel,
url: "includes/test-data.json",
initialize: function(){
console.log("Collection Hotel initialize");
},
parse: function(response){
return(response);
}
});这只是一个示例,你可以从中做更多的事情。
现在在你的渲染函数中....
您可以将任何内容放入下划线呈现方法。
例如:
render : function() {
//this will give you a nice formatted array (see toJSON override above)
var viewModel = this.collection.toJSON();
this.$el.html(this.template({models:viewModel});
}在您现在的视图中,您可以访问您的“房间”数组...
<script type="text/template" id="hotel-list-template">
<% _.each(models, function(hotel) { %>
<div id="hotel-container-<%= hotel.id %>">
<p>Nome Hotel: <%= hotel.name %></p>
<ul>
<% _.each(hote.rooms, function(room) { %>
<li><%=room.name%></li>
<% }); %>
</ul>
</div>
<% }); %>
</script>发布于 2013-07-01 06:26:24
您可以创建一个房间模型,然后创建一个房间集合。然后添加房间作为HotelView的属性。然后调用一个fetch并使用filter:
var HotelView = Backbone.View.extend({
template: _.template($("#hotel-list-template").html()),
initialize: function(){
this.collection = new HotelsCollection();
this.collection.bind('sync', this.render, this);
this.collection.fetch();
this.rooms = new RoomsCollection();
this.rooms.fetch();
var self = this;
this.rooms = this.rooms.filter(function(room){
return room.get("hotel_id") === self.get("id");
})
},然后,您只需将房间添加到div。如果你的应用很复杂,你可以为房间创建视图。
下面是filter函数的docs。
编辑:为一个房间创建样板。然后在酒店模板中放入一个带有#rooms id的空div。然后,对于每个房间,在此div中使用append模板。
https://stackoverflow.com/questions/17394461
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