用php从html页面中提取图像url

Question

如何使用php从此链接中提取帖子图像？

我读到我不能用正则表达式做这件事。

http://www.huffingtonpost.it/2013/07/03/stupri-piazza-tahrir-durante-proteste-anti-morsi_n_3538921.html?utm_hp_ref=italy

非常感谢。

Answer 1

$content=file_get_contents($url);
if (preg_match("/<img.*src=\"(.*)\".*class=\".*pinit\".*>/", $content, $matches)) 
{
echo "Match was found <br />";
echo $matches[0];
}

$matches将打印整个图像标记。如果您只想提取网址，那么您可以使用$matches1来获得相同的:)

Answer 2

你可以也必须用DOM解析你的html，下面是你的例子：

$curlResource = curl_init('http://www.huffingtonpost.it/2013/07/03/stupri-piazza-tahrir-durante-proteste-anti-morsi_n_3538921.html?utm_hp_ref=italy');
curl_setopt($curlResource, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curlResource, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($curlResource, CURLOPT_AUTOREFERER, true);

$page = curl_exec($curlResource);
curl_close($curlResource);


$domDocument = new DOMDocument();
$domDocument->loadHTML($page);

$xpath = new DOMXPath($domDocument);

$urlXpath = $xpath->query("//img[@id='img_caption_3538921']/@src");

$url = $urlXpath->item(0)->nodeValue;

echo $url;

花点时间学习一些DOM和XPATH，这是值得的。

Answer 3

试试这个。

$content=file_get_contents($url);
if (preg_match("/src=[\"\'][^\'\']+[\"\']/", $content, $matches)) 
{
    echo "Match was found <br />";
    echo $matches[0];
}