图(数字)转word java代码

Question

我想把数字转换成单词-到1缺少crore平均值高达1000000000000，如果我传递一个像这样的数字，函数应该在word中返回thin=s数字

我已经知道的代码高达900000000，但我想这里的限制是我写的代码…有没有人能让这个代码能够将1000000000000转换成word

public class NumberToWord  

{
    private static final String[] specialNames = {
        "",
        " thousand",
        " million",
        " billion",
        " trillion",
        " quadrillion",
        " quintillion"
    };

    private static final String[] tensNames = {
        "",
        " ten",
        " twenty",
        " thirty",
        " forty",
        " fifty",
        " sixty",
        " seventy",
        " eighty",
        " ninety"
    };

    private static final String[] numNames = {
        "",
        " one",
        " two",
        " three",
        " four",
        " five",
        " six",
        " seven",
        " eight",
        " nine",
        " ten",
        " eleven",
        " twelve",
        " thirteen",
        " fourteen",
        " fifteen",
        " sixteen",
        " seventeen",
        " eighteen",
        " nineteen"
    };

    private String convertLessThanOneThousand(int number) {
        String current;

        if (number % 100 < 20){
            current = numNames[number % 100];
            number /= 100;
        }
        else {
            current = numNames[number % 10];
            number /= 10;

            current = tensNames[number % 10] + current;
            number /= 10;
        }
        if (number == 0) return current;
        return numNames[number] + " hundred" + current;
    }

    public String convert(int number) {

        if (number == 0) { return "zero"; }

        String prefix = "";

        if (number < 0) {
            number = -number;
            prefix = "negative";
        }

        String current = "";
        int place = 0;

        do {
            int n = number % 1000;
            if (n != 0){
                String s = convertLessThanOneThousand(n);
                current = s + specialNames[place] + current;
            }
            place++;
            number /= 1000;
        } while (number > 0);

        return (prefix + current).trim();
    }

    public static void main(String[] args) {
        NumberToWord obj = new NumberToWord();
        System.out.println("*** " + obj.convert(123456789));
        System.out.println("*** " + obj.convert(-55));
    }
}

Answer 1

您可以使用long作为数据类型。

private String convertLessThanOneThousand(long number) {
    String current;

    if (number % 100 < 20){
        current = numNames[(int) (number % 100)];
        number /= 100;
    }
    else {
        current = numNames[(int) (number % 10)];
        number /= 10;

        current = tensNames[(int) (number % 10)] + current;
        number /= 10;
    }
    if (number == 0) return current;
    return numNames[(int) number] + " hundred" + current;
}

public String convert(long number) {

    if (number == 0) { return "zero"; }

    String prefix = "";

    if (number < 0) {
        number = -number;
        prefix = "negative";
    }

    String current = "";
    int place = 0;

    do {
        long n = number % 1000;
        if (n != 0){
            String s = convertLessThanOneThousand(n);
            current = s + specialNames[place] + current;
        }
        place++;
        number /= 1000;
    } while (number > 0);

    return (prefix + current).trim();
}

public static void main(String[] args) {
    NumberToWord obj = new NumberToWord();
    System.out.println("*** " + obj.convert(123456789));
    System.out.println("*** " + obj.convert(-55));
    System.out.println("*** " + obj.convert(1000000000000L));
}

输出：

*** one hundred twenty three million four hundred fifty six thousand seven hundred eighty nine
*** negative fifty five
*** one trillion

注意1000000000000末尾的L，以防您的编辑器抛出integer too long错误。

Answer 2

你可以考虑使用ICU4J，而不是自己做所有的事情。ICU4J是一个提供Unicode和全球化支持的库。

ICU为几种语言环境提供了数字拼写规则。下面是一个英语的例子：

 import com.ibm.icu.text.NumberFormat;
 import com.ibm.icu.text.RuleBasedNumberFormat;
 import com.ibm.icu.util.ULocale;

 public class NewClass4 {       
    public static void main(String[] args){
    ULocale locale = new ULocale("En");
    String input = "1000000000000";
    Long d = Long.parseLong(input);
    NumberFormat formatter = new RuleBasedNumberFormat(locale, RuleBasedNumberFormat.SPELLOUT);
    String result = formatter.format(d);
    System.out.println(result);
 }
}

输出：one trillion

您还可以将其用于双精度值。为

Double d = Double.parseDouble("123.45");

输出：one hundred twenty-three point four five