这是堆排序的mips代码。当我尝试运行它时,我在149行得到以下错误消息语法错误(数组:.word 54,23,56,32,99,7,4,2,88,9,11,21,39,55,100,101,43,1,3,69,-5,-24,-17,0),并且在第14行得到另一个指令引用未定义的符号。我已经看过它很多次了,仍然没有看到任何错误。如果你找到了,请告诉我。代码如下:
.text
.globl main
main:
la $a0, array # a0 = &array
la $t0, size
lw $a1, 0($t0) # a1 = size(array)
jal heapsort
# print the array
move $t0, $a0
add $t1, $zero, $zero
printloop:
li $v0, 1
lw $a0, 0($t0)
addi $t0, $t0, 4
addi $t1, $t1, 1
syscall
li $v0, 4
la $a0, space
syscall
bne $t1, $a1, printloop # while( t1 != size )
li $v0, 4
la $a0, newline
syscall
done:
jr $ra
heapsort: # a0 = &array, a1 = size(array)
addi $sp, $sp, -8
sw $a1, 0($sp) # save size
sw $a2, 4($sp) # save a2
sw $ra, 8($sp) # save return address
move $a2, $a1 # n will be stored in a2
addi $a2, $a2, -1 # n = size - 1
ble $a2,$zero, end_heapsort # if (n <= 0 ) return;
jal make_heap # a0 = arr, a1 = size
add $a1, $zero, $zero # clear $a1
heapsort_loop:
# swap(array[0],array[n])
lw $t0, 0($a0)
sll $t1, $a2, 2 #t1 = bytes(n)
add $t1, $t1, $a0
lw $t2, 0($t1)
sw $t0, 0($t1)
sw $t2, 0($a0)
addi $a2, $a2, -1 # n--
jal bubble_down # a0 = &array, a1 = 0, a2 = n
bnez $a2, heapsort_loop
end_heapsort:
lw $ra, 8($sp)
lw $a2, 4($sp)
lw $a1, 0($sp)
addi $sp, $sp, 8
jr $ra
make_heap: # a0 = &array, a1 = size
addi $sp, $sp, -12
sw $a1, 0($sp)
sw $a2, 4($sp)
sw $ra, 8($sp)
addi $a2, $a1, -1 # a2 = size - 1
addi $a1, $a1, -1 # start_index = size - 1
srl $a1, $a1, 1 # start_index /= 2
blt $a1, $zero, end_make_heap # if(start_index < 0) return
make_heap_loop:
jal bubble_down # a0 = &array, a1 = start_index, a2 = size-1
addi $a1, $a1, -1
ble $zero, $a1, make_heap_loop
end_make_heap:
lw $ra, 8($sp)
lw $a2, 4($sp)
lw $a1, 0($sp)
addi $sp, $sp, 12
jr $ra
#bubble_down is a leaf in the call graph
bubble_down: # a0 = &array, a1 = s_idx, a2 = end
move $t0, $a1 # index = s_idx
sll $t1, $t0, 2 # child = index*2+1
addi $t1, $t1, 1
bgt $t1, $a2, end_bubble_down
bubble_down_loop:
#if ( child < end && arr[child] < arr[child+1] )
ble $a2, $t1, skipinc
sll $t3, $t1, 2 # get bytes(child)
add $t3, $t3, $a0
lw $t3, 0($t3) # t3 = arr[child]
sll $t4, $t1, 2 #get bytes(child)
addi $t4, $t4, 4 #t4 = bytes(child+1)
add $t4, $t4, $a0
lw $t4, 0($t4) #t4 = arr[child+1]
ble $t4, $t3, skipinc
addi $t1, $t1, 1 # child++
skipinc:
sll $t3, $t0, 2 # get bytes(index)
add $t3, $t3, $a0
lw $t4, 0($t3) #t4 = arr[index], t3 = &arr[index]
sll $t5, $t1, 2 # get bytes(child)
add $t5, $t5, $a0
lw $t6, 0($t5) #t6 = arr[child], t5 = &arr[child]
ble $t6, $t4, end_bubble_down
# swap(arr[index],arr[child]
# note: t4 = arr[index], t6 = arr[child], t3 = &arr[index], t5 = &arr[child]
sw $t4, 0($t5)
sw $t6, 0($t3)
move $t0, $t1 # index = child
sll $t1, $t0, 1 # child = index*2+1
addi $t1, $t1, 1
ble $t1, $a2, bubble_down_loop
end_bubble_down:
jr $ra
.data
# the array that holds unordered data
array: .word 54,23,56,32,99,7,4,2,88,9,11,21,39,55,100,101,43,1,3,69,-5,-24,-17,0
size: .word 24
space: .asciiz " "
newline: .asciiz "\n"发布于 2016-11-14 10:19:17
语法错误可以通过在数组.word中的每个",“后面加一个空格来修复:因此"54,23,56,32,99,7,4,2,...”
发布于 2016-11-13 18:18:27
我无法重现你在Windows9.1.12版QtSpim中描述的错误。因此,您要么使用行为不同的不同版本的QtSpim,和/或没有运行您向我们展示的完全相同的代码,和/或没有在重新加载汇编代码之前重新初始化模拟器。
但是,您的代码中确实有一个bug。嗯,可能不止一个,但至少有一个是显而易见的:
在done:中,您可以尝试以jr $ra结束您的程序。但是,您在jal heapsort中更改了$ra的值,而没有保留它。所以在最后一个jr $ra中发生的事情是,您将跳回打印代码,然后该代码将再次执行。您要做的第一件事是$t0 = $a0,其中$a0应该包含array的地址。但是$a0不再包含数组的地址,因为就在jr $ra之前,您执行了la $a0, newline。
TL;DR:每当你做一个jal,你就是在修改$ra。如果以后需要$ra的前一个值,则需要保留它(在另一个寄存器、内存变量或堆栈中)。
https://stackoverflow.com/questions/40568738
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