如何使rp和xrange动态化？

Question

嘿，伙计们，非常感谢你们抽出时间来看我的问题，我已经在这个代码上工作了大约1周(我对编码和python 1周也是新手)，目前循环只有在x in xrange(x)和'rp‘时才能工作：'x’是这个xml中可用的正确行数。xml每天都在更新，我想知道是否有人可以提供一个解决方案来使x动态化？

import mechanize
import urllib
import json
import re
from sched import scheduler
from time import time, sleep

from sched import scheduler
from time import time, sleep

s = scheduler(time, sleep)

def run_periodically(start, end, interval, func):
event_time = start
while event_time < end:
    s.enterabs(event_time, 0, func, ())
    event_time += interval
s.run()

def getData():  
post_url = "urlofinterest_xml"
browser = mechanize.Browser()
browser.set_handle_robots(False)
browser.addheaders = [('User-agent', 'Firefox')]

######These are the parameters you've got from checking with the aforementioned tools
parameters = {'page' : '1',
              'rp' : '8',
              'sortname' : 'roi',
              'sortorder' : 'desc'
             }
#####Encode the parameters
data = urllib.urlencode(parameters)
trans_array = browser.open(post_url,data).read().decode('UTF-8')

xmlload1 = json.loads(trans_array)
pattern1 = re.compile('>&nbsp;&nbsp;(.*)<')
pattern2 = re.compile('/control/profile/view/(.*)\' title=')
pattern3 = re.compile('<span style=\'font-size:12px;\'>(.*)<\/span>')
pattern4 = re.compile('title=\'Naps posted: (.*) Winners:')
pattern5 = re.compile('Winners: (.*)\'><img src=')


for i in xrange(8):
    user_delimiter = xmlload1['rows'][i]['cell']['username']
    selection_delimiter = xmlload1['rows'][i]['cell']['race_horse']

    username_delimiter_results = re.findall(pattern1, user_delimiter)[0]
    userid_delimiter_results = int(re.findall(pattern2, user_delimiter)[0])
    user_selection = re.findall(pattern3, selection_delimiter)[0]
    user_numberofselections = float(re.findall(pattern4, user_delimiter)[0])
    user_numberofwinners = float(re.findall(pattern5, user_delimiter)[0])

    strikeratecalc1 = user_numberofwinners/user_numberofselections
    strikeratecalc2 = strikeratecalc1*100

    print "user id = ",userid_delimiter_results
    print "username = ",username_delimiter_results
    print "user selection = ",user_selection
    print "best price available as decimal = ",xmlload1['rows'][i]['cell']     ['tws.best_price']
    print "race time = ",xmlload1['rows'][i]['cell']['race_time']
    print "race meeting = ",xmlload1['rows'][i]['cell']['race_meeting']
    print "ROI = ",xmlload1['rows'][i]['cell']['roi']
    print "number of selections = ",user_numberofselections
    print "number of winners = ",user_numberofwinners
    print "Strike rate = ",strikeratecalc2,"%"
    print ""


getData()


run_periodically(time()+5, time()+1000000, 15, getData)

Kind关于AEA

Answer 1

首先，我将讨论如何迭代您的结果。根据您的代码，xmlload1['rows']是一个字典数组，因此您可以直接迭代它，而不是选择一个任意数字。

xmlload1 = {
   "rows": [{"cell": {"username": "one", "race_horse":"b"}}, {"cell": {"username": "two", "race_horse": "c"}}]
}

因此，给定上述数据，您可以在for循环中遍历各行，如下所示：

for row in xmlload1['rows']:
    cell = row["cell"]
    print cell["username"]
    print cell["race_horse"]

def get_data(rp=8, page=1):
    parameters = {'page' : str(page),
              'rp' : str(rp),
              'sortname' : 'roi',
              'sortorder' : 'desc'
             }
    data = urllib.urlencode(parameters)
    trans_array = browser.open(post_url,data).read().decode('UTF-8')
    return json.loads(trans_array)

现在，您可以调用get_data(rp=5)获取5行，或者调用get_data(rp=8)获取8行，调用get_data(rp=8, page=3)获取第三页，依此类推。您可以清楚地添加额外的变量，甚至可以直接将parameters dict传递给函数。

Answer 2

我不确定我是否理解了你的问题，但我认为你想要的是：

rows = xmlload1['rows']
for row in rows:
    user_delimiter = row['cell']['username']
    selection_delimiter = row['cell']['race_horse']
    # ...

如果不仅需要行本身，还需要行索引，请使用enumerate

rows = xmlload1['rows']
for i, row in enumerate(rows):
    user_delimiter = row['cell']['username']
    selection_delimiter = row['cell']['race_horse']
    # ...

一般而言，如果您使用for i in range(…)的目的不是为了固定的迭代次数，那么您这样做是错误的。通常有一个你想要遍历的集合；只要找到它并遍历它。