RPNCalculator代码混淆

Question

这是我的第二个编程课程，我是Java新手。我一直在做我的第一个任务，它涉及到类和方法。我对这些话题知之甚少，发现自己迷失了方向。我的任务要求我创建一个RPN计算器，要求用户输入两个数字和一个运算符。计算器对这两个数字执行运算，并要求再输入一个数字和一个运算符。然后，计算器使用第一个集合的结果，并使用刚刚输入的新数字执行另一个操作。当用户输入一个字母时，程序结束。我附上我的代码(粗糙)。我需要更多的帮助来理解方法，就像我需要编码一样。请尽快帮助我，我想学这个。任何帮助都是非常感谢的。

import java.util.Scanner;

public class RPNCalc 
{
    public static void main(String[]args)
    {
        Scanner keyboard = new Scanner(System.in);

        double v1, v2;
        String operator = keyboard.nextLine();
        char symbol = operator.charAt(0);

        System.out.print("Enter a value v1: ");
        v1 = keyboard.nextDouble();
        System.out.println();
        System.out.print("Enter a value v2: ");
        v2 = keyboard.nextDouble();
        System.out.println();
        System.out.print("Enter one of the valid operators +, -, *, /, nCr,:  ");
        operator = keyboard.nextLine();
        switch (symbol)
            {
             case'+':
                sum.writeOutput();
                break;
             case'-':
                minus.writeOutput();
                break;
             case'*':
                times.writeOutput();
                break;
             case'/':
                divide.writeOutput();
                break;
             case'q':
                System.out.println("Your last result was "  );
             default:
                System.out.println("You must choose an appropriate operator .");
             }
    }

    double value1, value2;
    int n;

    public static double sum(double value1,double value2)
    {
        double newSum = value1 + value2;
        return newSum;
    }
    public static double minus(double value1, double value2)
    {
        double newMinus = value1 - value2;
        return newMinus;
    }
    public static double times(double value1, double value2)
    {
        double newTimes = value1 * value2;
        return newTimes;
    }
    public static double divide(double value1, double value2)
    {
        double newDivide = value1 / value2;
        return newDivide;
    }
}

Answer 1

好的。我们开始吧。我对你的程序做了一点修改。以下是修改程序时出现的问题。1.在任何一个类中都没有"writeOutput()方法。因此，我必须删除这段代码。2.必须引入一个while循环来使这成为一个迭代过程。3.在读取操作符串之后，向下移动operator.charAt(0)方法。

由于您使用的是switch语句，因此不能将运算符值与"nCr“字符串值进行比较。要使用此方法，必须使用equals()方法进行字符串比较。

最后但并非最不重要的是，操作的结果应该是下一轮计算的输入之一。这意味着第一个操作的结果将被传递到下一个操作的第一个参数中。

import java.util.Scanner;

public class RPNCalc 
{
    public static void main(String[]args)
    {
        Scanner keyboard = new Scanner(System.in);

        double v1, v2;
//        String operator = keyboard.nextLine();
//        char symbol = operator.charAt(0);
        char operator = ' ';//First time around, set this to an something other than 'q'
        String operatorString = " ";
        System.out.print("Enter a value v1: ");
        v1 = keyboard.nextDouble();
        System.out.println();
        while(operator != 'q')
        {
            System.out.print("Enter a value v2: ");
            v2 = keyboard.nextDouble();
            System.out.println();
            System.out.print("Enter one of the valid operators +, -, *, /, nCr,:  ");
            operatorString = keyboard.next();//nextLine() doesn't wait until the user hit enter
            operator = operatorString.charAt(0);
            switch (operator)
            {
             case'+':
                v1 = sum(v1, v2);
                System.out.println(v1);
                break;
             case'-':
                v1 = minus(v1, v2);
                System.out.println(v1);
                break;
             case'*':
                v1 = times(v1, v2);
                System.out.println(v1);
                break;
             case'/':
                v1 = divide(v1, v2);
                System.out.println(v1);
                break;
             case'q':
                System.out.println("Your last result was "  );                
             default:
                System.out.println("You must choose an appropriate operator .");
             }
        }
    }

    double value1, value2;
    int n;

    public static double sum(double value1,double value2)
    {
        double newSum = value1 + value2;
        return newSum;
    }
    public static double minus(double value1, double value2)
    {
        double newMinus = value1 - value2;
        return newMinus;
    }
    public static double times(double value1, double value2)
    {
        double newTimes = value1 * value2;
        return newTimes;
    }

    public static double divide(double value1, double value2)
    {
        if (value2 == 0)
        {
            System.out.println("Division by Zero. Try again");
            return value1;
        }
        double newDivide = value1 / value2;
        return newDivide;
    }
}

Answer 2

您正在将您的函数名视为某个类的对象。这个代码能编译吗？

当用户输入'q‘时，你想退出你的程序。

您可以从阅读开头的运算符开始。为什么？

您需要将程序的主体封装在一个循环中。

我将为您编写几行代码，但大部分更改将留给您作为练习

double result;
System.out.print("Enter the first value");
result = keyboard.nextDouble();
boolean done = false;

while (!done) {
    System.out.println("Enter a value");
    v1 = keyboard.nextDouble();
    System.out.print("Enter one of the valid operators +, -, *, /, nCr,:  ");
    operator = keyboard.nextLine();
    symbol = operator.charAt(0);
    switch (symbol) {
      case '+':
        result = sum(result, v1);
        break;
      ...
      case 'q':
        System.out.println("Your last result was " + result);
        done = true;
        break;
     }
}