我有一个脚本,使用api来获取ip地址的ip信息。当访问者输入时,它只显示有关访问者ip的默认信息,但我想制作一个表单,以便访问者可以通过在表单中输入IP并单击查找来查找特定的IP地址。
我不知道该怎么做,我需要你的帮助和感谢
index.php
<?php
require_once('ipapi.class.php');
$ip = $_REQUEST['REMOTE_ADDR']; // the IP address to query
$query = IPAPI::query("$rip");
echo "\t IP Information: " .$rip. "<br />";
echo "\t ISP: " .$query->isp . "<br />";
echo "\t Organization: " .$query->org . "<br />";
echo "\t City: " .$query->city . "<br />";
echo "\t Region: " .$query->regionName . "<br />";
echo "\t Country: " .$query->country . "<br />";
?>发布于 2013-05-09 09:31:39
你应该有一个html表单来实现它。您的index.php应该如下所示:
<?php
require_once('ipapi.class.php');
if(isset($_GET['ip']))
$rip = $_GET['ip'];
else
$rip = $_REQUEST['REMOTE_ADDR']; // the IP address to query
$query = IPAPI::query("$rip");
echo "\t IP Information: " .$rip. "<br />";
echo "\t ISP: " .$query->isp . "<br />";
echo "\t Organization: " .$query->org . "<br />";
echo "\t City: " .$query->city . "<br />";
echo "\t Region: " .$query->regionName . "<br />";
echo "\t Country: " .$query->country . "<br />";
?>
<form name="input" action="#" method="get">
IP: <input type="text" name="ip">
<input type="submit" value="Submit">
</form>我认为您在$ip变量中有一个错误,所以我改用$rip。
https://stackoverflow.com/questions/16452578
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