我有一个这样的查询
SELECT * FROM CC
INNER JOIN App (CC.id = App.id)
WHERE CC.counter >1000
AND 0 = IF(CC.key1 = App.key1,
(SELECT COUNT(*)
FROM Service
WHERE App.No = Service.No
)
),
(SELECT COUNT(*)
FROM Service
WHERE App.NoCo = Service.No
AND App.NoCo != ''
)
)
)如何在MYSQL中将有条件的内部查询转换为左连接?
我正在尝试将此子查询转换为join子句以获得更好的性能
发布于 2016-11-03 18:40:35
试试这个:
SELECT * FROM CC
INNER JOIN App (CC.id = App.id)
LEFT JOIN(SELECT s.no,count(*) as cnt_1,sum(s.no <> '') as cnt_2
FROM Service s
GROUP BY s.no) t
ON(0 = CASE WHEN CC.key1 = App.key1 THEN t.cnt_1 ELSE t.cnt_2 END)
WHERE CC.counter >1000发布于 2016-11-03 18:43:26
我会改用EXISTS
SELECT *
FROM CC INNER JOIN
App
ON CC.id = App.id
WHERE CC.counter > 1000 AND
( (CC.key1 = App.key1 AND
NOT EXISTS (SELECT 1
FROM Service
WHERE App.No = Service.No
) OR
(CC.key1 = App.key1 AND
NOT EXISTS (SELECT 1
FROM Service
WHERE App.NoCo = Service.No AND
App.NoCo <> ''
)
)
);为了提高性能,您需要一个关于Service(No)和CC(counter, id)的索引。
您必须小心使用LEFT JOIN,因为您的条件具有OR。这可能会无意中增加行数。
https://stackoverflow.com/questions/40399249
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