家庭作业
必须重载operator<<、operator==和operator!=
.h文件和.cpp文件包含在下面:
namespace JoePitz
{
class Complex
{
// declare friend functions
friend ostream &operator<<(ostream &out, const Complex &value);
friend ostream &operator<<(ostream &out, const bool &value);
friend istream &operator>>(istream &in, Complex &value);
public:
// constructor
Complex(double real, double imaginary);
// overloading +/-/==/!= operators
Complex operator+(const Complex &compx2);
Complex operator-(const Complex &compx2);
bool operator==(const Complex &compx2);
bool operator!=(const Complex &compx2);
private:
double real;
double imaginary;
void initialize(double real, double imaginary);
};
// GCC requires friend functions to be declared in name space
ostream &operator<<(ostream &out, const Complex &value);
ostream &operator<<(ostream &out, const bool &value);
istream &operator>>(istream &in, Complex &value);
}
excerpt from .cpp file
ostream& JoePitz::operator<<(ostream &out, const Complex &value)
{
// print real
cout << value.real;
// print imaginary
if (value.imaginary == ISZERO)
{
cout << POSSIGN << value.imaginary << IMAGNSGN;
}
else if (value.imaginary > ISZERO)
{
cout << POSSIGN << value.imaginary << IMAGNSGN;
}
else
{
cout << value.imaginary << IMAGNSGN;
}
return out;
}
ostream& JoePitz::operator<<(ostream &out, const bool &value)
{
return out;
}
// overloaded == operator
bool JoePitz::Complex::operator==(const Complex &compx2)
{
return (this->real == compx2.real && this->imaginary == compx2.imaginary);
}
// overloaded != operator
bool JoePitz::Complex::operator!=(const Complex &compx2)
{
return !(this->real == compx2.real && this->imaginary == compx2.imaginary);
}我收到以下编译错误:
../src/hw4.cpp:71:错误:'c1 <<“** *\012"‘../src/Complex.h:54:注意:候选项为: std::ostream& JoePitz::operator<<( std::ostream&,const bool&) ../src/Complex.h:53:注意:std::ostream& JoePitz::operator<<(std::ostream&,const JoePitz::Complex&)
据我所知,这是因为不知道要实现哪个重载函数。
我遇到的问题是如何处理这样一个事实: operator<<函数返回一个ostream并接受一个复杂对象,而operator==函数返回一个bool。
但是我不知道如何更改operator==函数来处理布尔和/或复杂对象。我试图添加另一个重载的返回布尔值的opperator<<函数,但编译器仍然有问题。
任何帮助都将不胜感激。
发布于 2013-05-05 13:19:40
这是一个简单的运算符优先级错误,这是
cout << "* * * Unit Test 3 comparison operations == != * * \n";
cout << " * * Print c1 == c1 = " << c1 == c1 << " * * *\n";应该是这样的
cout << "* * * Unit Test 3 comparison operations == != * * \n";
cout << " * * Print c1 == c1 = " << (c1 == c1) << " * * *\n";<<比==具有更高的优先级,因此您需要使用括号。
删除ostream bool过载。
另一个变化
Complex operator+(const Complex &compx2);
Complex operator-(const Complex &compx2);
bool operator==(const Complex &compx2);
bool operator!=(const Complex &compx2);都应该是const方法
Complex operator+(const Complex &compx2) const;
Complex operator-(const Complex &compx2) const;
bool operator==(const Complex &compx2) const;
bool operator!=(const Complex &compx2) const;https://stackoverflow.com/questions/16380944
复制相似问题