我有下面这段代码
XmlDocument docu = new XmlDocument();
docu.Load(file);
XmlNodeList lst = docu.GetElementsByTagName("name");
foreach (XmlNode n in lst)
{
string text = n.InnerText;
var types = doc.Element("program").Element("program-function").Element("function").Descendants("type").Where(x => x.Value == text).Select(c => c.Value).ToArray();
}我的xml如下所示
<program>
<program-function>
<function>
<name>add</name>
<return-type>double</return-type>
<params>
<type>double</type>
<type-value>a</type-value>
<type>double</type>
<type-value>b</type-value>
<type>string</type>
<type-value>c</type-value>
</params>
<body> return a + b + c; </body>
</function>
<function>
<name>test</name>
<return-type>int</return-type>
<params>
<type>double</type>
<type-value>a</type-value>
<type>double</type>
<type-value>b</type-value>
</params>
<body> return a + b; </body>
</function>
</program-function>
</program>我需要能够获得每个<name>的<type>数量
add的结果应为3= types.count() = 3
测试结果应为2= types.count() = 2
有什么建议吗?
编辑:如果我想检索types中的每个值?即。add应包含a、b、c,test应包含a、b。我喜欢将其存储在一个数组中,以便更容易地检索
发布于 2013-04-22 22:00:16
如何使用Linq to Xml
var xDoc = XDocument.Parse(xml);
var functions = xDoc.Descendants("function")
.Select(f => new
{
Name = f.Element("name").Value,
Types = f.Descendants("type").Select(t=>t.Value).ToList(),
//Types = f.Descendants("type").Count()
TypeValues = f.Descendants("type-value").Select(t=>t.Value).ToList()
})
.ToList();发布于 2013-04-22 22:00:00
试试这个:
XDocument doc = XDocument.Load(your file);
var vals = doc.Element("program").Element("program-function").Elements("function");
var result = vals.Select(i =>
new { name = i.Element("name"),
count = i.Elements("type").Count() }https://stackoverflow.com/questions/16148898
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