SQL如何根据目标源上的数量将数量拆分成多行

Question

我有两个表，我想加入和显示详细数量。表与ITM、DIA连接，且在ITM/DIA组合的两个表中总数量相等

我想拆分table1上的table2数量，并将table2数据与table1数据一起填充。

我有下面的数据供你参考，"table1“和"table2”。您可以在表"tableResult“中看到我的预期结果。

CREATE TABLE table1
    (`ITM` varchar(5), `DIA` varchar(4), `LOC` varchar(4), `ID` varchar(3), `QTY` int)
;

INSERT INTO table1
    (`ITM`, `DIA`, `LOC`, `ID`, `QTY`)
VALUES
    ('Item1', 'DIA1', 'LOC1', 'ID1', 3),
    ('Item1', 'DIA1', 'LOC2', 'ID2', 4),
    ('Item1', 'DIA1', 'LOC2', 'ID2', 6),
    ('Item1', 'DIA2', 'LOC2', 'ID2', 6),
    ('Item1', 'DIA2', 'LOC3', 'ID3', 18),
    ('Item1', 'DIA2', 'LOC4', 'ID4', 90),
    ('Item1', 'DIA2', 'LOC4', 'ID5', 23),
    ('Item1', 'DIA3', 'LOC5', 'ID6', 50),
    ('Item1', 'DIA3', 'LOC6', 'ID7', 20),
    ('Item2', 'DIA1', 'LOC4', 'ID8', 44),
    ('Item2', 'DIA2', 'LOC5', 'ID8', 21),
    ('Item2', 'DIA3', 'LOC6', 'ID9', 20)
;


CREATE TABLE table2
    (`ITM` varchar(5), `DIA` varchar(4), `NTA` varchar(5), `QTY` int)
;

INSERT INTO table2
    (`ITM`, `DIA`, `NTA`, `QTY`)
VALUES
    ('Item1', 'DIA1', 'NTA1', 10),
    ('Item1', 'DIA1', 'NTA2', 3),
    ('Item1', 'DIA2', 'NTA3', 30),
    ('Item1', 'DIA2', 'NTA4', 7),
    ('Item1', 'DIA2', 'NTA5', 100),
    ('Item1', 'DIA3', 'NTA6', 70),
    ('Item2', 'DIA1', 'NTA7', 22),
    ('Item2', 'DIA1', 'NTA8', 20),
    ('Item2', 'DIA2', 'NTA9', 6),
    ('Item2', 'DIA2', 'NTA10', 15),
    ('Item2', 'DIA3', 'NTA11', 8),
    ('Item2', 'DIA3', 'NTA11', 12)
;


CREATE TABLE tableResult
    (`ITM` varchar(5), `DIA` varchar(4), `LOC` varchar(4), `ID` varchar(3), `QTY` int, `NTA` varchar(5), `NewQTY` int)
;

INSERT INTO tableResult
    (`ITM`, `DIA`, `LOC`, `ID`, `QTY`, `NTA`, `NewQTY`)
VALUES
    ('Item1', 'DIA1', 'LOC1', 'ID1', 3, 'NTA1', 3),
    ('Item1', 'DIA1', 'LOC2', 'ID2', 4, 'NTA1', 4),
    ('Item1', 'DIA1', 'LOC2', 'ID2', 6, 'NTA1', 3),
    ('Item1', 'DIA1', 'LOC2', 'ID2', 6, 'NTA2', 3),
    ('Item1', 'DIA2', 'LOC2', 'ID2', 6, 'NTA3', 6),
    ('Item1', 'DIA2', 'LOC3', 'ID3', 18, 'NTA3', 18),
    ('Item1', 'DIA2', 'LOC4', 'ID4', 90, 'NTA3', 6),
    ('Item1', 'DIA2', 'LOC4', 'ID4', 90, 'NTA4', 7),
    ('Item1', 'DIA2', 'LOC4', 'ID4', 90, 'NTA5', 77),
    ('Item1', 'DIA2', 'LOC4', 'ID5', 23, 'NTA5', 23),
    ('Item1', 'DIA3', 'LOC5', 'ID6', 50, 'NTA6', 50),
    ('Item1', 'DIA3', 'LOC6', 'ID7', 20, 'NTA6', 20),
    ('Item2', 'DIA1', 'LOC4', 'ID8', 44, 'NTA7', 22),
    ('Item2', 'DIA1', 'LOC4', 'ID8', 44, 'NTA8', 20),
    ('Item2', 'DIA2', 'LOC5', 'ID8', 21, 'NTA9', 6),
    ('Item2', 'DIA2', 'LOC5', 'ID8', 21, 'NTA10', 15),
    ('Item2', 'DIA3', 'LOC6', 'ID9', 20, 'NTA11', 8),
    ('Item2', 'DIA3', 'LOC6', 'ID9', 20, 'NTA11', 12)
;

下面是数据截图；

​

我可以使用proc和跟随游标来实现，但是我想知道使用SQL 2014有什么简单的方法，而且我知道CTE递归技巧将会有所帮助。

您能分享一下您对此的解决方案吗？感谢您提出的宝贵的想法..

Answer 1

您只需以单位分解table1和table2的数量，然后将它们并排耦合。

注意FN_NUMBERS( n )，它是一个函数，它只返回一个从1到n的数字列，你需要在数据库中使用它，有很多方法可以做到这一点，只需在谷歌中搜索"tally tables“或look here即可。

我使用以下代码：

CREATE FUNCTION FN_NUMBERS(
     @MAX INT
)
RETURNS @N TABLE (N INT NOT NULL PRIMARY KEY)  
BEGIN
     WITH
       Pass0 as (select '1' as C union all select '1'),       --2 rows
       Pass1 as (select '1' as C from Pass0 as A, Pass0 as B),--4 rows
       Pass2 as (select '1' as C from Pass1 as A, Pass1 as B),--16 rows
       Pass3 as (select '1' as C from Pass2 as A, Pass2 as B),--256 rows
       Pass4 as (select TOP (@MAX) '1' as C from Pass3 as A, Pass3 as B)    --65536 rows
       ,Tally as (select TOP (@MAX) '1' as C from Pass4 as A, Pass2 as B, Pass1 as C)  --4194304 rows
       --,Tally as (select TOP (@MAX) '1' as C from Pass4 as A, Pass3 as B)               --16777216 rows
       --,Tally as (select TOP (@MAX) '1' as C from Pass4 as A, Pass4 as B)               --4294836225 rows
     INSERT INTO @N
     SELECT TOP (@MAX) ROW_NUMBER() OVER(ORDER BY C) AS N
     FROM Tally
     RETURN
END

回到sql..

;with
t1 as (
    select *, ROW_NUMBER() over (partition by itm,dia order by loc,id) rn      
    from table1 t1
    join FN_NUMBERS(500) on n<=t1.qty
),
t2 as (
    select *, ROW_NUMBER() over (partition by itm,dia order by nta) rn      
    from table2 t2
    join FN_NUMBERS(500) on n<=t2.qty
),
t3 as (
    select t1.itm, t1.dia, t1.loc, t1.id, t1.qty, t2.nta, count(t1.n) NewQTY
    from  t1
    join  t2 on t1.itm=t2.itm and t1.dia = t2.dia and t1.rn=t2.rn
    group by t1.itm, t1.dia, t1.loc, t1.id, t1.qty, t2.nta
)
select * 
from t3
order by 1,2,3,4,5,6