如何在xui js中读取xml

Question

我在PhoneGap中使用xui js，我想通过xui js读取xml。我写了一些代码，我正在为每个元素运行根元素successfully.And循环，我还获得了能够显示textContent.But的元素我无法在element.How中获得更多标记内的元素我可以获得如下that.My代码：

    xui(window).on('load', function(){
        var url="http://www.w3schools.com/dom/books.xml";
        fireURL(url,winner);
    });

    function fireURL(url,success)
    {   
        var option={
        async:true,
        callback:function(){
            success(this.responseText);
        }
        }
        x$().xhr(url,option);
    } 

   function winner(data)
    {    
         domParser = new DOMParser();
         var xmlDoc=domParser.parseFromString(data,"text/xml");

        x$(xmlDoc).find("book").each(function(element,index){
            alert(element.textContent);
            //Here I want to get further elements by its tag name
        });
    }

Answer 1

您可以轻松地使用Here中的javascript for that.Get reference

或者用以下代码替换您的成功代码：-

        function winner(data)
    {    
         domParser = new DOMParser();
         var xmlDoc=domParser.parseFromString(data,"text/xml");

         var _bookStore=[];

        x$(xmlDoc).find("book").each(function(element,index){
              var _book={};
              _book.author=[];
              _book.title=element.getElementsByTagName("title")[0].textContent;
              for(j=0;j<element.getElementsByTagName("author").length;j++){
                  _book.author.push(element.getElementsByTagName("author")[j].textContent);
              }
              _book.year=element.getElementsByTagName("year")[0].textContent;
              _book.price=element.getElementsByTagName("price")[0].textContent;
              _bookStore.push(_book);
        });

         alert("hello"+JSON.stringify(_bookStore));
    }