我在解决所有我的类实现可序列化的notSeriazable时遇到了问题,但它总是给我一个错误。
java.io.NotSerializableException: java.util.Scanner
at java.io.ObjectOutputStream.writeObject0(Unknown Source)
at java.io.ObjectOutputStream.defaultWriteFields(Unknown Source)
at java.io.ObjectOutputStream.writeSerialData(Unknown Source)
at java.io.ObjectOutputStream.writeOrdinaryObject(Unknown Source)
at java.io.ObjectOutputStream.writeObject0(Unknown Source)
at java.io.ObjectOutputStream.writeObject(Unknown Source)
at Assign3.main(Assign3.java:119)扫描仪是一个类,对,我没有意义..我认为扫描仪也应该序列化吗??但是我不能碰Scanner类。
Bank b = new Bank(100.0);
try{
ObjectOutputStream save = new ObjectOutputStream(new FileOutputStream("try.txt"));
save.writeObject(b);
save.close();
}catch(Exception ex){ex.printStackTrace();}
import java.io.Serializable;
import java.util.Scanner;
public class Bank implements Serializable{
/**
*
*/
private static final long serialVersionUID = 1L;
private int Maxtransaction = 1000;
public Transaction[] transactions = new Transaction[Maxtransaction];
private int numTransactions = 0;
private double balance;
Scanner sn = new Scanner(System.in);
public Bank()
{
}
public Bank(double balance)
{
this.balance = balance;
}
public double getBalance()
{
return balance;
}
public void display()
{
System.out.print("\nTRANSACTION RECORD:\n");
for(int i = 0; i<numTransactions;i++)
{
System.out.print(transactions[i].toString()+"\n");
}
System.out.print("BALANCE : $"+getBalance()+"\n");
}
public boolean addTransaction(Category categories)
{
if(numTransactions>Maxtransaction){return false;}
else{
String[] chooseaccountletter = {"c","d"};
String chooseaccount;
boolean erroraccount = true;
System.out.print("\n");
do{
System.out.print("Enter a c for credit or d for debit: ");
chooseaccount = sn.nextLine();
for(int i = 0 ; i<chooseaccountletter.length;i++)
{
if(chooseaccountletter[i].equals(chooseaccount))
{
erroraccount = false;
break;
}
}
}while(erroraccount);
if(chooseaccountletter[0].equals(chooseaccount))
{
Transaction credit = new CreditTransaction();
credit.getTransactionInfo(categories);
credit.getAmout();
balance += credit.getAmout();
transactions[numTransactions] = credit;
}//end credit
if(chooseaccountletter[1].equals(chooseaccount))
{
Transaction debit = new DebitTransaction();
debit.getTransactionInfo(categories);
debit.getAmout();
balance += debit.getAmout();
transactions[numTransactions] = debit;
}//end debit
numTransactions++;
return true;
}
}
public void displayCategory(String Category)
{
double total = 0;
System.out.print("\nTransactions for Category "+Category+" :\n");
for(int i = 0; i<numTransactions;i++){
if(transactions[i].getCategory() == Category)
{
System.out.print(transactions[i].toString()+"\n");
total += transactions[i].getAmout();
}
}
System.out.print("Category Balance : $"+total+"\n");
}
}发布于 2013-04-04 06:49:38
没有Scanner没有实现Serializable,所以如果您的Bank类包含一个Scanner对象,那么它也是不可序列化的。您必须删除Scanner或将其标记为transient或static,才能使Bank对象可序列化。(请注意,将扫描器标记为静态将使其属于类,而不是Bank的单个实例。您可能会更好地将其设为暂时的。)
发布于 2013-04-04 06:48:34
请显示Bank有哪些成员。如果它的任何成员没有实现Serializable,那么类本身就不能被序列化,除非显式地用瞬态标记为排除。
发布于 2013-04-04 06:52:08
将Bank类中的Scanner对象标记为transient以使其可序列化,或者将Scanner对象移动到方法中。
https://stackoverflow.com/questions/15799541
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