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NotSerializableException on java scanner?
EN

Stack Overflow用户
提问于 2013-04-04 06:43:20
回答 3查看 4.8K关注 0票数 1

我在解决所有我的类实现可序列化的notSeriazable时遇到了问题,但它总是给我一个错误。

代码语言:javascript
复制
 java.io.NotSerializableException: java.util.Scanner
 at java.io.ObjectOutputStream.writeObject0(Unknown Source)
at java.io.ObjectOutputStream.defaultWriteFields(Unknown Source)
at java.io.ObjectOutputStream.writeSerialData(Unknown Source)
at java.io.ObjectOutputStream.writeOrdinaryObject(Unknown Source)
at java.io.ObjectOutputStream.writeObject0(Unknown Source)
at java.io.ObjectOutputStream.writeObject(Unknown Source)
at Assign3.main(Assign3.java:119)

扫描仪是一个类,对,我没有意义..我认为扫描仪也应该序列化吗??但是我不能碰Scanner类。

代码语言:javascript
复制
Bank b = new Bank(100.0);
    try{
        ObjectOutputStream save = new ObjectOutputStream(new FileOutputStream("try.txt"));

        save.writeObject(b);


        save.close();

        }catch(Exception ex){ex.printStackTrace();}



import java.io.Serializable;
import java.util.Scanner;



public class Bank implements Serializable{
/**
 * 
 */
private static final long serialVersionUID = 1L;
private int Maxtransaction = 1000;
public Transaction[] transactions = new Transaction[Maxtransaction];
private int numTransactions = 0;
private double balance;
Scanner sn = new Scanner(System.in);

public Bank()
{
}

public Bank(double balance)
{
    this.balance = balance;
}

public double getBalance()
{
    return balance;
}

public void display()
{
    System.out.print("\nTRANSACTION RECORD:\n");
    for(int i = 0; i<numTransactions;i++)
        {
        System.out.print(transactions[i].toString()+"\n"); 
        }
    System.out.print("BALANCE : $"+getBalance()+"\n");

}

public boolean addTransaction(Category categories)
{
    if(numTransactions>Maxtransaction){return false;}
    else{
    String[] chooseaccountletter = {"c","d"};
    String chooseaccount;
    boolean erroraccount = true;

    System.out.print("\n");
    do{
    System.out.print("Enter a c for credit or d for debit: ");
        chooseaccount = sn.nextLine();
        for(int i = 0 ; i<chooseaccountletter.length;i++)
            {
              if(chooseaccountletter[i].equals(chooseaccount))
              {
                  erroraccount = false;
                  break;
              }
            }
      }while(erroraccount);

    if(chooseaccountletter[0].equals(chooseaccount))
    {
        Transaction credit = new CreditTransaction();
        credit.getTransactionInfo(categories);
        credit.getAmout();
        balance += credit.getAmout();
        transactions[numTransactions] = credit;
    }//end credit

    if(chooseaccountletter[1].equals(chooseaccount))
    {
        Transaction debit = new DebitTransaction();
        debit.getTransactionInfo(categories);
        debit.getAmout();
        balance += debit.getAmout();
        transactions[numTransactions] = debit;
    }//end debit
    numTransactions++;
    return true;
    }

}

public void displayCategory(String Category)
{   
    double total = 0;
    System.out.print("\nTransactions for Category "+Category+" :\n");


    for(int i = 0; i<numTransactions;i++){
        if(transactions[i].getCategory() == Category)
            {
                System.out.print(transactions[i].toString()+"\n");
                total += transactions[i].getAmout(); 
            }
        }

    System.out.print("Category Balance : $"+total+"\n");
}

}
EN

回答 3

Stack Overflow用户

回答已采纳

发布于 2013-04-04 06:49:38

没有Scanner没有实现Serializable,所以如果您的Bank类包含一个Scanner对象,那么它也是不可序列化的。您必须删除Scanner或将其标记为transientstatic,才能使Bank对象可序列化。(请注意,将扫描器标记为静态将使其属于类,而不是Bank的单个实例。您可能会更好地将其设为暂时的。)

票数 3
EN

Stack Overflow用户

发布于 2013-04-04 06:48:34

请显示Bank有哪些成员。如果它的任何成员没有实现Serializable,那么类本身就不能被序列化,除非显式地用瞬态标记为排除。

票数 1
EN

Stack Overflow用户

发布于 2013-04-04 06:52:08

将Bank类中的Scanner对象标记为transient以使其可序列化,或者将Scanner对象移动到方法中。

票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/15799541

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