Weather API和HttpURLConnection

Question

所以我打算做一个应用程序，为你提供当前所在位置的天气。现在我知道了我的当前坐标，并编写了以下代码：

MainActivity.java

//..... (previous codes obtain the coordinate, and working)
RetrieveWeather mRetrieveWeather = new RetrieveWeather();
t.append("" + mRetrieveWeather.getWeatherReport(mCoordinate));

RetrieveWeather.java

package com.example.maest.weather;

import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;

/**
 * Created by maest on 2016/9/28.
 */
public class RetrieveWeather {
        public String getWeatherReport(double[] mCoordinate){
        HttpURLConnection mHttpUrlConnection = null;
        InputStream mInputStream = null;

        try{
            mHttpUrlConnection = (HttpURLConnection) (new URL("http://api.openweathermap.org/data/2.5/forecast?lat=38.868884&lon=-77.053086&appid=myid)).openConnection();
            mHttpUrlConnection.setRequestMethod("GET");
            mHttpUrlConnection.setDoInput(true);
            mHttpUrlConnection.connect();

            StringBuffer mStringBuffer = new StringBuffer();
            mInputStream = mHttpUrlConnection.getInputStream();
            BufferedReader mBufferedReader = new BufferedReader(new InputStreamReader(mInputStream));
            String mString = null;
            while ((mString = mBufferedReader.readLine()) != null)
                mStringBuffer.append(mString + "\n");

            mInputStream.close();
            mHttpUrlConnection.disconnect();
            return mStringBuffer.toString();
        }catch (Throwable t){
            t.printStackTrace();
        }finally{
            try { mInputStream.close();}catch(Throwable t) {}
            try { mHttpUrlConnection.disconnect();}catch(Throwable t) {}
        }

        return "You failed again!";
    }
}

请注意，该url是有效的，尽管我在此处替换了我的appid。

每次我运行这段代码时，TextView都会显示“你又失败了！”。

为什么？

(附注：我在Manifest中确实有足够的用户权限)

Answer 1

我建议使用一个库来提出你的网络请求，这将为你省去很多麻烦。以http://square.github.io/retrofit/为例查看Retrofit