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onBackPressed()显示错误
EN

Stack Overflow用户
提问于 2013-03-21 13:05:56
回答 4查看 1.4K关注 0票数 0

我想在单击mainactivity中的back按钮时添加一个退出警告。为此,我使用以下代码

代码语言:javascript
复制
@Override
public void onBackPressed() {
    // TODO Auto-generated method stub

    final Dialog dialoge=new Dialog(MainActivity.this,android.R.style.Theme_Translucent_NoTitleBar);
    dialoge.setContentView(R.layout.popup_layout);

    Button yes=(Button)dialoge.findViewById(R.id.yes);
    yes.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub

            MainActivity.this.finish();

        }
    });
    Button no=(Button)dialoge.findViewById(R.id.no);
    no.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub
            dialoge.cancel();
        }
    });


    dialoge.show();
}

这是有效的,但在退出时显示一些错误。

Logcat是

代码语言:javascript
复制
  03-21 10:25:57.192: E/WindowManager(14488): Activity com.example.design.MainActivity has leaked window com.android.internal.policy.impl.PhoneWindow$DecorView@447fec28 that was originally added here
03-21 10:25:57.192: E/WindowManager(14488): android.view.WindowLeaked: Activity com.example.design.MainActivity has leaked window com.android.internal.policy.impl.PhoneWindow$DecorView@447fec28 that was originally added here
03-21 10:25:57.192: E/WindowManager(14488):     at android.view.ViewRoot.<init>(ViewRoot.java:251)
03-21 10:25:57.192: E/WindowManager(14488):     at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:148)
03-21 10:25:57.192: E/WindowManager(14488):     at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:91)
03-21 10:25:57.192: E/WindowManager(14488):     at android.view.Window$LocalWindowManager.addView(Window.java:424)
03-21 10:25:57.192: E/WindowManager(14488):     at android.app.Dialog.show(Dialog.java:241)
03-21 10:25:57.192: E/WindowManager(14488):     at com.example.design.MainActivity.onBackPressed(MainActivity.java:97)
03-21 10:25:57.192: E/WindowManager(14488):     at android.app.Activity.onKeyUp(Activity.java:1895)
03-21 10:25:57.192: E/WindowManager(14488):     at android.view.KeyEvent.dispatch(KeyEvent.java:1283)
03-21 10:25:57.192: E/WindowManager(14488):     at android.app.Activity.dispatchKeyEvent(Activity.java:2075)
03-21 10:25:57.192: E/WindowManager(14488):     at com.android.internal.policy.impl.PhoneWindow$DecorView.dispatchKeyEvent(PhoneWindow.java:1673)
03-21 10:25:57.192: E/WindowManager(14488):     at android.view.ViewRoot.deliverKeyEventToViewHierarchy(ViewRoot.java:2493)
03-21 10:25:57.192: E/WindowManager(14488):     at android.view.ViewRoot.handleFinishedEvent(ViewRoot.java:2463)
03-21 10:25:57.192: E/WindowManager(14488):     at android.view.ViewRoot.handleMessage(ViewRoot.java:1752)
03-21 10:25:57.192: E/WindowManager(14488):     at android.os.Handler.dispatchMessage(Handler.java:99)
03-21 10:25:57.192: E/WindowManager(14488):     at android.os.Looper.loop(Looper.java:143)
03-21 10:25:57.192: E/WindowManager(14488):     at android.app.ActivityThread.main(ActivityThread.java:4914)
03-21 10:25:57.192: E/WindowManager(14488):     at java.lang.reflect.Method.invokeNative(Native Method)
03-21 10:25:57.192: E/WindowManager(14488):     at java.lang.reflect.Method.invoke(Method.java:521)
03-21 10:25:57.192: E/WindowManager(14488):     at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:858)
03-21 10:25:57.192: E/WindowManager(14488):     at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:616)
03-21 10:25:57.192: E/WindowManager(14488):     at dalvik.system.NativeStart.main(Native Method)
EN

回答 4

Stack Overflow用户

回答已采纳

发布于 2013-03-21 13:17:14

你不会忽略这个对话框,这是警告所说的泄漏。

代码语言:javascript
复制
@Override
    public void onClick(View v) {
        // TODO Auto-generated method stub

        // here you need to dismiss your dialog before finishing activity
        if (dialoge != null) {
            dialoge.cancel();
            dialoge = null;
        }

        MainActivity.this.finish();

    }
票数 6
EN

Stack Overflow用户

发布于 2013-03-21 13:16:41

你可以给它一个try just call yes按钮,如下所示:

代码语言:javascript
复制
Button yes=(Button)dialoge.findViewById(R.id.yes);
    yes.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub
            dialoge.cancel();
            MainActivity.this.finish();

        }
    });

对话框需要在退出应用程序之前取消。这就是为什么它会在对话框打开时显示leaked window error

票数 2
EN

Stack Overflow用户

发布于 2013-03-21 13:21:25

关闭对话框,在完成活动后调用dailog.dismiss()dialog.cancel(),我测试了你的代码,它应该如下所示:

代码语言:javascript
复制
@Override
public void onBackPressed() {
    final Dialog dialoge=new Dialog(SecondActivity.this,android.R.style.Theme_Translucent_NoTitleBar);
    dialoge.setContentView(R.layout.popup_layout);

    Button yes=(Button)dialoge.findViewById(R.id.yes);
    yes.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub

            finish();
            dialoge.cancel();

        }
    });
    Button no=(Button)dialoge.findViewById(R.id.no);
    no.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub
            finish();
            dialoge.dismiss();
        }
    });


    dialoge.show();

}
票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/15539934

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